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Advocard [28]
4 years ago
12

√ ​36 rational irrational real natural whole integer

Mathematics
1 answer:
aleksandr82 [10.1K]4 years ago
5 0
Whole number since the square root is 6
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PLS HELP ME ASAP WITH 42!! (MUST SHOW WORK!!) + LOTS OF POINTS!! *best if show picture with work!!*
ddd [48]
I thought this would be simple, as I'm familiar with algebra and not really "The constant of proportionality," but I will do my best.

So this said "Constant of proportionality," is referring to basically the answers for the equation when X equals certain numbers.

Make a table of different answers when you plug in X and you get the 'Constant of proportionality.'

y = 2.5x + 3
y = 2.5(1) + 3
y = 2.5 + 3
y = 5.5

Since we plugged in 1 for X and got 5.5 for Y, our input and output is (1, 5.5)

Replace X for a different value, and you will get a bunch of different numbers that will in essence be your function inputs and outputs.  Make a table of these and you have your answer.

EXAMPLE - 
-= x =-   -= y =-
-= 1 =-   -= 5.5 =-
-= 2 =-   -= 8 =-
-= 3 =-   -= 11.5 =-
-= 4 =-   -= 13 =-


So there you have it.  I hope this helps!  If you have any further questions, don't hesitate to ask.
3 0
3 years ago
For the figures below, assume they are made of semicircles, quarter circles and squares. For each shape, find the area and perim
ICE Princess25 [194]

Answer:

Part a) The area of the figure is \frac{9}{2}(4+\pi )\ cm^{2}

Part b) The perimeter of the figure is 3(2+2\sqrt{2}+ \pi)\ cm

Step-by-step explanation:

Step 1

Find the area of the figure

In this problem we have that

The figure ABC is the half of a square and the other figure is a semicircle

<u>Find the area of the figure ABC</u>

we have

AB=6\ cm, BC=6\ cm

The area of the half square ABC is equal to find the area of triangle ABC

so

A1=\frac{1}{2}*6*6=18\ cm^{2}

<u>Find the area of the semicircle</u>

The area of the semicircle is equal to

A2=\pi r^{2}/2

we have that

r=6/2=3\ cm

substitute

A2=\pi (3)^{2}/2

A2=(9/2) \pi\ cm^{2}

The area of the figure is equal to

18\ cm^{2}+(9/2) \pi\ cm^{2}= \frac{9}{2}(4+\pi )\ cm^{2}

Step 2

Find the perimeter of the figure

The perimeter of the figure is equal to

P=AB+AC+length\ CB

we have

AB=6\ cm

Applying Pythagoras theorem

AC=\sqrt{6^{2}+6^{2}}\\AC=6\sqrt{2}\ cm

Remember that

the circumference of a semicircle is equal to

C=\frac{1}{2}2\pi r=\pi r

r=6/2=3\ cm

C=\pi(3)

C=3 \pi\ cm

The perimeter of the figure is equal to

P=6\ cm+6\sqrt{2}\ cm+3 \pi\ cm

Simplify

P=3(2+2\sqrt{2}+ \pi)\ cm

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3 years ago
1.How many solutions does the system have?
MaRussiya [10]

Answer:

c. infinitely many solutions

Step-by-step explanation:

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Zinaida [17]

Answer:

d

Step-by-step explanation:

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4 years ago
What is the sum of: <br> −1676+(−1669)+(−1662)+...+(−115)+(−108)
Sedaia [141]

Answer: i believe its -5230

Step-by-step explanation:

3 0
3 years ago
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