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anygoal [31]
3 years ago
9

Claire is cycling at a speed of 12 miles per hour. Han is cycling at a speed of 8 miles per hour. If they start at the same posi

tion, chosen at zero, and bike in straight opposite directions, what will the distance between them be after 45 minutes?
Mathematics
2 answers:
larisa [96]3 years ago
8 0

Answer:

45 minutes is 3/4 of an hour, so find 3/4 of 12.  

Divide 12 by 4 to get 1/4 of 12. That is 3.  

3/4 is 3 of those, so multiply it by 3 to get 9.

So, she will have biked 9 miles.  

Molodets [167]3 years ago
4 0

Answer:

180 miles.

Step-by-step explanation:

First, we have to find out how far Claire is after 45 minutes:

12 x 45 = <u>540</u>

Now, we need to find out how far Han is after 45 minutes:

8 x 45 = <u>360</u>

Lastly, we need to subtract how far Claire went by how far Han went:

540 - 360 = <u>180</u>

Final answer:

The distance between Claire and Han after 45 minutes will be 180 miles.

Hope this helped! Have a nice day!

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V125BC [204]
54/2 or 27 should be the answer
3 0
3 years ago
Pleaseee help answer correctly !!!!!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!
Alexeev081 [22]

Answer:

108º

Step-by-step explanation:

to find the sum of interior angles: ( n − 2 ) × 180 = x

x = 540º

n = # of interior angles

first, solve for n

(n - 2) • 180 = 540                        distribute to 180 to (n - 2)

180n - 360 = 540                         add 360 to both sides

180n = 900                                  divide both sides by 180

n = 5

to find measure of each angle:

540 ÷ 5 = 108º

5 0
3 years ago
Solve each of the following equations.
tamaranim1 [39]
A. -13
B. -45
C. 20
D. 84
E. 4
F. -4
G. -7
H. 48
6 0
3 years ago
Read 2 more answers
What is 48% of 64 please give right answers only
Charra [1.4K]

Answer:

30.72

Step-by-step explanation:

7 0
3 years ago
Please solve this sheet.
lyudmila [28]
Hello,

A: roots: -1,-3
a point (-2,1)
Vertex=((-2,1)

y=k*(x+1)(x+3) using roots
but k*(-2+1)(-2+3)=1==>k*(-1)*1=1==>k=-1

eq: y=-(x+1)(x+3)
==>y=-(x²+3x+x+3)
==>y=-x²-4x-3
y=k(x+2)²+1 if x=-1,y=0 ==>k*1+1=0==>k=-1
==>y=-(x+2)²+1

Answer :A--> R,K

B)
y=k(x+4)²-2 and k=-1/2
y=-1/2(x+4)²-2
y=-1/2x²-4x-10

answer B--> I,≈W if it is written -1/2*x²  (square has been forgotten)

C:
y=2x²-16x+30
y=2(x-4)²-2
answer : C-->S,J

D:
y=-(x+3)(x+1)
y=-x²-4x-3
=-(x+2)²+1
answer D--> V,L

E:
Here there is a problem: or the graph is wrong, or 2 equations are missing!

y=1(x+1)(x-3) using roots
y=x²-2x-3 ≈ T si it were -2x and not +2x.

y=(x-1)²-4 ≈H is it were -1 in place of +1 [H:y=(x+1)²-4]




6 0
3 years ago
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