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3 years ago

X + 4y = 17 8x - 7y = 58

Mathematics

1 answer:

Marianna [84]3 years ago

8 0

Problem 1 Answer: x = 17 + -4y

Show Work:

1) Simplifying

x + 4y = 17

2) Solving

x + 4y = 17

3) Solving for variable 'x'.

4) Move all terms containing x to the left, all other terms to the right.

5) Add '-4y' to each side of the equation.

x + 4y + -4y = 17 + -4y

6) Combine like terms: 4y + -4y = 0

x + 0 = 17 + -4y

x = 17 + -4y

7) Simplifying

x = 17 + -4y

Problem 2 Answer: x = 7/8y + 29/4

Step 1: Add 7y to both sides.

8x−7y+7y=58+7y

8x=7y+58

Step 2: Divide both sides by 8.

8x/8 = 7y+58/8

x = 7/8y + 24/9

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Answer:

See attachment showing the rise and run

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In the diagram attached below, the rise is represented by the blue line, while the run is represented by the red line.

Rise = 4 units

Run = 4 units

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In Triangle DEF, the sum of the measures of Angle D and Angle E is 110. The sum of the measures of Angle E and Angle F is 150. F

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Answer:

<D + <F = $100^{o}$

Step-by-step explanation:

Given: <D + <E = $110^{o}$

<E + <F = $150^{o}$

But, the sum of angles in a triangle = $180^{o}$ .

Thus;

<D + <E + <F = $180^{o}$

$110^{o}$ + <F = $180^{o}$

⇒ <F = $180^{o}$ - $110^{o}$

= $70^{o}$

<F = $70^{o}$

Also,

<E + <F = $150^{o}$

<E + $70^{o}$ = $150^{o}$

<E = $150^{o}$ - $70^{o}$

= $80^{o}$

<E = $80^{o}$

So that;

<D + <E = $110^{o}$

<D + $80^{o}$ = $110^{o}$

<D = $110^{o}$ - $80^{o}$

= $30^{o}$

<D = $30^{o}$

⇒ <D = $30^{o}$ , <E = $80^{o}$ , and <F = $70^{o}$ .

Therefore;

<D + <F = $30^{o}$ + $70^{o}$

= $100^{o}$

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