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ikadub [295]
2 years ago
10

Given cosθ=√3/3 and sinθ<0. What is the value of sinθ?

Mathematics
1 answer:
KATRIN_1 [288]2 years ago
5 0

\sin^{2} \theta+\cos^{2} \theta=1 \\ \\ \sin^{2} \theta+\left(\frac{\sqrt{3}}{3} \right)^{2}=1 \\ \\ \sin^{2} \theta+\frac{1}{3}=1 \\ \\ \sin^{2} \theta=\frac{2}{3} \\ \\ \theta=-\frac{\sqrt{2}}{\sqrt{3}}=\boxed{-\frac{\sqrt{6}}{3}}

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Answer:

Step-by-step explanation:

50 X 4= 200

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3 0
3 years ago
2(x-3)-12 = -4<br> How do I solve this equations
deff fn [24]

Answer:

x= 7

Step-by-step explanation:

1st step: Multiply the factor (outside number) with the numbers and variable(s) in the box. This results in 2(x-3) = 2x-6

2nd Step: continue the rest of the equation since there are no more brackets left so 2x-6-12=-4

3rd Step: send -12 to the other side of the equation (side changes sign changes) so it will become 2x-6=-4+12    (You are actually supposed to make the variable alone on one side of the equation so that you would be able to calculate its value)

4th step: 2x-6=8 ---> send -6 to the other side as well which will then result in 2x=14

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Final Step: x=7

3 0
3 years ago
when a number is written in scientific notation how can you tell right away weather or not it is greater than or equal to one
lidiya [134]
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Hope this helps!
4 0
3 years ago
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masya89 [10]
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3 years ago
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alexdok [17]
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7 0
3 years ago
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