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77julia77 [94]
4 years ago
5

Find the solution to the following system using substitution or elimination:

Mathematics
1 answer:
jasenka [17]4 years ago
7 0

Answer: (-2,1) OR x=-2,y=1

Step-by-step explanation: Solve for the first variable in one of the equations, then substitute the result into the other equation.

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Retrying this question because no one wanted to help on the last one.
RUDIKE [14]

Answer:

.

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Create a system of linear equations with no solution. In your final answer, include the system of equations and the graphs of th
Georgia [21]

Answer:

sdgggggggggggggggggggggggggggg

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
A. f(x) = 2|2| is differentiable overf<br> X<br> B. g(x) = 2 + || is differentiable over<br> -f
kramer

Recall the definition of absolute value:

• If <em>x</em> ≥ 0, then |<em>x</em>| = <em>x</em>

• If<em> x</em> < 0, then |<em>x</em>| = -<em>x</em>

<em />

(a) Splitting up <em>f(x)</em> = <em>x</em> |<em>x</em>| into similar cases, you have

• <em>f(x)</em> = <em>x</em> ² if <em>x</em> ≥ 0

• <em>f(x)</em> = -<em>x</em> ² if <em>x</em> < 0

Differentiating <em>f</em>, you get

• <em>f '(x)</em> = 2<em>x</em> if <em>x</em> > 0 (note the strict inequality now)

• <em>f '(x)</em> = -2<em>x</em> if <em>x</em> < 0

To get the derivative at <em>x</em> = 0, notice that <em>f '(x)</em> approaches 0 from either side, so <em>f</em> <em>'(x)</em> = 0 if <em>x</em> = 0.

The derivative exists on its entire domain, so <em>f(x)</em> is differentiable everywhere, i.e. over the interval (-∞, ∞).

(b) Similarly splitting up <em>g(x)</em> = <em>x</em> + |<em>x</em>| gives

• <em>g(x)</em> = 2<em>x</em> if <em>x</em> ≥ 0

• <em>g(x)</em> = 0 if <em>x</em> < 0

Differentiating gives

• <em>g'(x)</em> = 2 if <em>x</em> > 0

• <em>g'(x)</em> = 0 if <em>x</em> < 0

but this time the limits of <em>g'(x)</em> as <em>x</em> approaches 0 from either side do not match (the limit from the left is 0 while the limit from the right is 2), so <em>g(x)</em> is differentiable everywhere <u>except</u> <em>x</em> = 0, i.e. over the interval (-∞, 0) ∪ (0, ∞).

5 0
3 years ago
What is equivalent to -1/4y -2 1/4y + 1/2 (4-2y) a) -3y + 2 b) -3 1/2y + 2 c) -4y + 4
Amanda [17]

Answer:

B. -3 1/2y + 2

Step-by-step explanation:

Our expression is: \frac{-1}{4} y-2\frac{1}{4} y+\frac{1}{2} (4-2y).

Let's first distribute out that parentheses. Remember that distribution is simply taking the sum of the product of the outside term with each of the inside terms. Here, the outside term is 1/2 and the inside terms are 4 and -2y:

\frac{1}{2} (4-2y)=\frac{1}{2} *4+\frac{1}{2} *(-2y)=2-y

Now, we have:

\frac{-1}{4} y-2\frac{1}{4} y+2-y

We want to combine like terms, which means combining all the terms with y in them:

\frac{-1}{4} y-2\frac{1}{4} y-y+2=\frac{-1}{4} y-\frac{9}{4} y-\frac{4}{4} y+2=\frac{-1-9-4}{4} y+2=\frac{-14}{4} y+2=\frac{-7}{2} y+2

Remember that -7/2 can be written as the mixed number -3 1/2, so our final answer is:

-3 1/2y + 2

The answer is thus B.

<em>~ an aesthetics lover</em>

7 0
3 years ago
4. A fruit vendor packed 100 apples each in 64 baskets. Later, he found some apples were left unpacked. So he packed 30 more app
topjm [15]

Answer:

Here is the answer

Step-by-step explanation:

Apples in 1 baskets=100

Apples in 64 baskets=100*64-6400

apples (before adding 30 apples in each

basket).... ..(1)

Some apples left unpacked

So he added 30 apples to each

Total apples added by him- 30*64(in each basket*no of baskets)

= 1920 apples

.(2)

So total no apples eq(1)+eq(2)

= 6400 apples + 1920 apples

=8320 apples packed in total

Therefore the total no. of apples packed were 8320 apples.

Hope this helps

Thanks

4 0
2 years ago
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