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scoray [572]
3 years ago
5

Create an equation that represents a parabola that opens upward

Mathematics
1 answer:
algol133 years ago
8 0

For a parabola that opens upward, it must be a quadratic equation whose coefficient of x2 is a positive number.

So, I'll say x2+5x+6.

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nexus9112 [7]
I dont understand your question.......
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3 years ago
Algebra
vladimir2022 [97]
(2x + 3y = 12) x (-2)
(4x - 3y = 6) x 1

-4x - 6y = -24
4x - 3y = 6

You can cancel out the x values by adding the two equations together. 
(-4x + 4x) + (-6y - 3y) = (-24 + 6)
-9y = -18
y = 2

Solve for x now...
4x - 3(2) = 6
4x - 6 = 6
4x = 12
x = 3

Check... (x = 3, y = 2)
2(3) + 3(2) = 12 
6 + 6 = 12
12 = 12 <- this works! 

4(3) - 3(2) = 6
12 - 6 = 6
6 = 6 <- this works!
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Step-by-step explanation:

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