Solve the equation
1" title="(\frac{1}{125})^{3x+2}=25^{x}" alt="(\frac{1}{125})^{3x+2}=25^{x}" align="absmiddle" class="latex-formula">
1 answer:
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-22 - x = 5 + 6x + 9 Combine like terms (5 and 9)
-22 - x = 14 + 6x Subtract 6x from both sides
-22 - 7x = 14 Add 22 to both sides
-7x = 36 Divide both sides by -7
x = 5
-22 - x = 14 + 6x Subtract 6x from both sides
-22 - 7x = 14 Add 22 to both sides
-7x = 36 Divide both sides by -7
x = 5