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3 years ago

Solve the equation

1" title="(\frac{1}{125})^{3x+2}=25^{x}" alt="(\frac{1}{125})^{3x+2}=25^{x}" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

Vilka [71]3 years ago

3 0

Answer:

Step-by-step explanation:

（-3）*（3x+2） = 2x

x = -6/11

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WILL MARK BRAINLIEST!!!

denis23 [38]

Answer:

Okay the question is a little unclear, but if he's only doing english, science and history the answer should be <u> 17/40</u>

Step-by-step explanation:

1/5=8/40

3/8=15/40

8/40+15/40=23/40

40/40-23/40=17/40

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Wow.... My brother Said that it took him a while to figure it out... but

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Dmitrij [34]

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3 years ago

Use the exponential decay model, Upper A equals Upper A 0 e Superscript kt, to solve the following. The half-life of a certai

Akimi4 [234]

Answer:

It will take 7 years ( approx )

Step-by-step explanation:

Given equation that shows the amount of the substance after t years,

$A=A_0 e^{kt}$

Where,

$A_0$ = Initial amount of the substance,

If the half life of the substance is 19 years,

Then if t = 19, amount of the substance = $\frac{A_0}{2}$ ,

i.e.

$\frac{A_0}{2}=A_0 e^{19k}$

$\frac{1}{2} = e^{19k}$

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Taking ln both sides,

$\ln(0.5) = \ln(e^{19k})$

$\ln(0.5) = 19k$

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Then $A=78\% \text{ of }A_0 =\frac{78A_0}{100}=0.78 A_0$

$0.78 A_0=A_0 e^{-0.03648t}$

$0.78 = e^{-0.03648t}$

Again taking ln both sides,

$\ln(0.78) = -0.03648t$

$-0.24846=-0.03648t$

$\implies t = \frac{0.24846}{0.03648}=6.81085\approx 7$

Hence, approximately the substance would be 78% of its initial value after 7 years.

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3 years ago

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dsp73

Answer:

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Step-by-step explanation:

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