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Lilit [14]
3 years ago
10

today Kylee put a kitchen table on layaway by making a down payment of 120 and agreeing to pay $48 a month starting next month f

or 24 months when will I receive the kitchen table​
Mathematics
2 answers:
yawa3891 [41]3 years ago
8 0

Answer:

2 1/2 months by the 3rd month

Step-by-step explanation:

kherson [118]3 years ago
5 0

Answer:

Kylee will receive the table in 24 months.

Step-by-step explanation:

Layaway is a type of purchasing method where the buyer places a deposit on an item to secure it or lay it aside. The buyer will pick up the item later when he pays the full balance.

This system allows the buyer to make smaller payments on the item until the full amount has been paid off.

So, if Kylee put the kitchen table on layaway, and agrees to pay $48 a month starting next month for 24 months. She will get the table in 24 months after completing her payment.

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QUESTION 1 -
tester [92]
<h3>#1</h3>

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f(-2) = 3(-2)² -5(-2) + 4

f(-2) = 12 + 10 + 4

f(-2) = 26

Answer: 26

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For an ordered pair (x, y) in a relation, the y element represents the range.

Answer: range

5 0
2 years ago
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zubka84 [21]

Answer:

The answer is 3, 6.

Step-by-step explanation:

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3 years ago
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White raven [17]

Answer:

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Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A friend of mine is giving a dinner party. His current wine supply includes 9 bottles of zinfandel, 10 of merlot, and 12 of cabe
e-lub [12.9K]

Answer:

Step-by-step explanation:

From the given information:

The total number of wine = 9 + 10 + 12 = 31

(1)

The number of distinct sequences used for serving any five wines can be estimated by using the permutation of the number of total wines with the number of wines served.

i.e

= ^{31}P_5

=\dfrac{31!}{(31-5)!}

=\dfrac{31!}{(26)!}

=\dfrac{31\times 30\times 29\times 28\times 27\times 26!}{(26)!}

= 20389320

(2)

If the first two wines served = zinfandel and the last three is either merlot or cabernet;

Then, the no of ways we can achieve this is:

= ^9P_2\times ^{22}P_3

= \dfrac{9!}{(9-2)!}\times \dfrac{22!}{(22-3)!}

= \dfrac{9!}{(7)!}\times \dfrac{22!}{(19)!}

= \dfrac{9*8*7!}{(7)!}\times \dfrac{22*21*20*19!}{(19)!}

= 665280

(3)

The probability that no zinfandel is served is computed as follows:

Total wines (with zinfandel exclusion) = 31 - 9 = 22

Now;

the required probability is:

= \dfrac{^{22}P_5 }{^{31}P_5}

= \dfrac{\dfrac{22!}{(22-5)!} } {\dfrac{31!}{(31-5)!} }

= \dfrac{\dfrac{22!}{17!} } {\dfrac{31!}{(26)! }}

= \dfrac{(\dfrac{22*21*20*19*18*17!}{17!})} {(\dfrac{31*30*29*28*27*26!}{(26)! })}

= 0.1549

≅ 0.155

4 0
3 years ago
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Karolina [17]

Answer:

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Step-by-step explanation:

(I hope this is right, I wasn't quite sure of the context)

7 0
3 years ago
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