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3 years ago

A 12 pack of diet soda has dimensions 4.75in and 28.5in whats the volume of the 12 pack round to the nearest ten

Mathematics

1 answer:

ExtremeBDS [4]3 years ago

6 0

Answer:

$Volume = 643.0\ in^3$

Step-by-step explanation:

Given

Dimension: 4.75in, 4.75in and 28.5in

<em>[The complete dimension is missing from the question]</em>

Required

Calculate the volume

The volume is calculated as thus:

$Volume = 4.75in * 4.75in * 28.5in$

$Volume = 643.03125in^3$

$Volume = 643.0\ in^3$ --- approximated

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Eduardwww [97]

Answer:

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Step-by-step explanation:

15xy-4+2xy-7xy-1 is the given expression.

I assume the directions say to simplify.

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3 years ago

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Given two vectors a⃗ = 4.60 i^+ 7.20 j^ and b⃗ = 5.10 i^− 2.70 j^ , find the scalar product of the two vectors a⃗ and b⃗ .

grin007 [14]

A=<4.60,7.20>
b=<5.10,2.70>
The scalar product, or the inner product, or the dot-product, is by summing the products of the respective directions,
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3 years ago

Use spherical coordinates. Find the volume of the solid that lies within the sphere x^2 + y^2 + z^2 = 81, above the xy-plane, an

Natasha_Volkova [10]

Answer:

The volume of the solid is 243 $\sqrt{2} \ \pi$

Step-by-step explanation:

From the information given:

BY applying sphere coordinates:

0 ≤ x² + y² + z² ≤ 81

0 ≤ ρ² ≤ 81

0 ≤ ρ ≤ 9

The intersection that takes place in the sphere and the cone is:

$x^2 +y^2 ( \sqrt{x^2 +y^2 })^2 = 81$

$2(x^2 + y^2) =81$

$x^2 +y^2 = \dfrac{81}{2}$

Thus; the region bounded is: 0 ≤ θ ≤ 2π

This implies that:

$z = \sqrt{x^2+y^2}$

ρcosФ = ρsinФ

tanФ = 1

Ф = π/4

Similarly; in the X-Y plane;

z = 0

ρcosФ = 0

cosФ = 0

Ф = π/2

So here; $\dfrac{\pi}{4} \leq \phi \le \dfrac{\pi}{2}$

Thus, volume: $V = \iiint_E \ d V = \int \limits^{\pi/2}_{\pi/4} \int \limits ^{2\pi}_{0} \int \limits^9_0 \rho ^2 \ sin \phi \ d\rho \ d \theta \ d \phi$