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Sloan [31]
3 years ago
8

Identify the phase shift of each function. Describe each phase shift use a phrase like 3 units to the left

Mathematics
1 answer:
melisa1 [442]3 years ago
7 0

Answer:

It moves horizontally 1/2 units to the left

It moves vertically 2 units up

Step-by-step explanation:

∵ y = Acos(Bx - C) + D

∵ y = 2 - 3cos(2x + 1)

∴ The phrase of shift:

∵ The horizontally shift is -C/B = - 1/2 = -1/2

∴ It moves 1/2 units to the left

∵ The vertically shift is D

∴ It moves 2 units up

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what's the question pymp

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A book that cost $58 is now increased by 25 what is the new cost
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the new cost is 83

Step-by-step explanation:

58 plus 25 is 83

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- 1 1/2 +3 1/2 - 5/8
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Answer:

1 3/8

Step-by-step explanation:

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Suppose that a company needs 1, 200,000 items during a year and that preparation for each production run costs $500. Suppose als
MAVERICK [17]

Answer:

The number of items in each production run so that the total costs of production and storage are minimized is 8165 items/run

Step-by-step explanation:

We will use the following variables:

Q = Quantity being ordered

Q* = the optimal order Quantity: the result being sought

D = annual Demand for the item, over the year

P = unit Production cost

S = cost of setting up a production run, regardless of the number of units in the production run (fixed cost per production run)

H = annual cost to Hold one unit

It is important to note which variables are annualized, which are per-order and which are per-unit.

Using the variables, here are the components of the first equation

Total Cost, TC = PC + SC + HC

PC = P x D :  Production Cost = unit Production cost times the annual Demand

SC = (D x S)/Q : Setting up Cost = annual Demand times cost per production setup, divided by the order Quantity (number of units)

HC = (H x Q)/2: Holding Cost = annual unit Holding cost times order Quantity (number of units), divided by 2 (because throughout the year, on average the warehouse is half full).

So TC = PC + SC + HC =  (P x D) + ((D x S)/Q) + ((H x Q)/2) = PD + (DS/Q) + HQ/2

To obtain the optimal order quantity, Q* that minimizes TC, at the minimum TC, dTC/dQ = 0

dTC/dQ = (H/2) – (D x S)/(Q²) = 0

(H/2) – (D x S)/(Q²) = 0

Solving for Q, which is Q* at this point.

(Q*)² = 2DS/H

Q* = √(2DS/H)

D = annual demand for the item = 200000

S = cost of setting up a production run, regardless of the number of units in the production run (fixed cost per production run) = $500

H = annual cost to Hold one unit = $3

Q* = √(2×200000×500/3) = 8164.97 = 8165 items.

3 0
3 years ago
A bag contains 56 marbles: 7 red, green, 11 yellow, 17 brown, and 13 blue.
pav-90 [236]

Answer:

8/56

Step-by-step explanation:

Add up all other marble colors then find the difference from the total.

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