How many different ways can i select 2 of 6 candy bars?

Mathematics

1 answer:

Westkost [7]3 years ago

8 0

You have 12 ways to select 2 of 6 candy bars.

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Simplify the expression below. (2x^3-12x^2+10x-108)/x-6

ser-zykov [4K]

We have the following expression:
(2x ^ 3-12x ^ 2 + 10x-108) / x-6
Dividing the expression between x-6 we have:
quotient: 2x ^ 2 + 10
remainder: - 48
We can check the result then rewriting the expression:
2x ^ 3-12x ^ 2 + 10x-108
= (2x ^ 2 + 10) * (x-6) - 48
= (2x ^ 3 + 10x - 12 x ^ 2 - 60) - 48
= 2x ^ 3-12x ^ 2 + 10x-108
Division OK.
Answer:
The result of the division is:
quotient: 2x ^ 2 + 10
remainder: - 48

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Minchanka [31]

Answer:

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Step-by-step explanation:

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3 years ago

The number of cigarettes smoked per day by adults forms a normal distribution. The average number of cigarettes smoked per day i

Mariana [72]

Answer:

17.3 cigarettes represent the 35th percentile

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 20, \sigma = 7$