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vivado [14]
3 years ago
12

How to find the area of a semi circle in the terms of pi

Mathematics
2 answers:
never [62]3 years ago
3 0

Answer:

A = pi × r²÷2

Step-by-step explanation:

This is the formula this might help you

Anna35 [415]3 years ago
3 0
In the case of a circle, the formula for area, A, is A = pi * r^2, where r is the circle's radius. Since we know that a semicircle is half of a circle, we can simply divide that equation by two to calculate the area of a semicircle. So, the formula for the area of a semicircle is A = pi * r^2/2
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What expressions is equivalent to -3 3/7 + 2 5/7
bonufazy [111]

Answer:

-5/7

Step-by-step explanation:

-3 3/7 + 2 5/7

-3 - 3/7 + 2 + 5/7

-3 + 2 + 5/7 - 3/7

-1 + 2/7

-5/7

5 0
3 years ago
I have more to come help please:(
Serggg [28]
Maaaaane I’m sorry I can’t help
4 0
3 years ago
Which describes the best relationship between the age of cheese and the amount of lactic acid present in the cheese
katrin2010 [14]
Positive correlation
6 0
3 years ago
A jar has 15 red marbles,5 blue marbles,10 green marbles.what is the ratio of red marbles to the total number of marbles in simp
Misha Larkins [42]

Answer:

1:2

Step-by-step explanation:

The total number of marbles in the jar can be found by adding all the numbers of marbles given:

15+5+10 = 30

Out of 30 total marbles, 15 are red marbles. We can write the ratio as:

15:30

This ration can be simplified to:

1:2

7 0
3 years ago
Evaluate the line integral for x^2yds where c is the top hal fo the circle x62 _y^2 = 9
natulia [17]
Parameterize C by

\mathbf r(t)=\langle x(t),y(t)\rangle=\langle3\cos t,3\sin t\rangle

where 0\le t\le\pi. Then the line integral is

\displaystyle\int_Cx^2y\,\mathrm dS=\int_{t=0}^{t=\pi}x(t)^2y(t)\left\|\frac{\mathrm d\mathbf r(t)}{\mathrm dt}\right\|\,\mathrm dt
=\displaystyle\int_{t=0}^{t=\pi}(3\cos t)^2(3\sin t)\sqrt{(-3\sin t)^2+(3\cos t)^2}\,\mathrm dt
=\displaystyle3^4\int_{t=0}^{t=\pi}\cos^2t\sin t\,\mathrm dt

Take u=\cos t, then

=\displaystyle-3^4\int_{u=1}^{u=-1}u^2\,\mathrm du
=\displaystyle3^4\int_{u=-1}^{u=1}u^2\,\mathrm du
=\displaystyle2\times3^4\int_{u=0}^{u=1}u^2\,\mathrm du
=54
6 0
3 years ago
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