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Lynna [10]
3 years ago
13

The seasonal output of a new experimental strain of pepper plants was carefully weighed. The mean weight per plant is 15.0 pound

s, and the standard deviation of the normally distributed weights is 1.75 pounds. Of the 200 plants in the experiment, how many produced peppers weighing between 13 and 16 pounds
Mathematics
1 answer:
DanielleElmas [232]3 years ago
4 0

Answer:

There are 118 plants that weight between 13 and 16 pounds

Step-by-step explanation:

For any normal random variable X with mean μ and standard deviation σ : X ~ Normal(μ, σ)  

This can be translated into standard normal units by :  

Z = \frac{(X - \mu)}{\sigma}

Let X be the weight of the plant  

X ~ Normal( 15 , 1.75 )  

To find : P( 13 < X < 16 )  

= P(\frac{( 13 - 15 )}{1.75} < Z < \frac{( 16 - 15 )}{1.75})

= P( -1.142857 < Z < 0.5714286 )  

= P( Z < 0.5714286 ) - P( Z < -1.142857 )  

= 0.7161454 - 0.1265490  

= 0.5895965  

So, the probability that any one of the plants weights between 13 and 16 pounds is 0.5895965  

Hence, The expected number of plants out of 200 that will weight between 13 and 16 = 0.5895965 × 200

                                            = 117.9193  

Therefore, There are 118 plants that weight between 13 and 16 pounds.

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8 0
3 years ago
If zeba were younger by 5 years than what she really is then the square of her age would have been 11 more than five times her a
RSB [31]

Answer:

14 years old

Step-by-step explanation:

<u>Define the variable</u>

Let x be the actual age of Zeba (in years).

<u>Create an equation</u> using the give information and the variable x:

(x - 5)^2=5x+11

To find Zeba's age now, <u>solve the equation for x</u>.

Expand the brackets:

\implies x^2-10x+25=5x+11

Subtract 5x from both sides:

\implies x^2-10x+25-5x=5x+11-5x

\implies x^2-15x+25=11

Subtract 11 from both sides:

\implies x^2-15x+25-11=11-11

\implies x^2-15x+14=0

<u>Factor the found quadratic</u>

To factor a quadratic in the form ax^2+bx+c<em>, </em>find two numbers that multiply to ac and sum to b, then rewrite b as the sum of these two numbers:

\implies x^2-14x-x+14=0

Factor the first two terms and the last two terms separately:

\implies x(x-14)-1(x-14)=0

Factor out the common term (x - 14):

\implies (x-1)(x-14)=0

Apply the <u>zero product property</u>:

\implies (x-1)=0 \implies x=1

\implies (x-14)=0 \implies x=14

Therefore, Zeba's age now is either 1 or 14 years.

As the question states "If Zeba were younger by 5 years" then 1 must be an <u>extraneous solution</u> since 1 - 5 = -4 and Zeba cannot be -4 years old.

Therefore, Zeba's age now is 14 years old.

<u>Check</u>

Given the actual age of Zeba is 14 years old.

Therefore, If Zeba were younger by 5 years, she would be 9 years old as:  14 - 5 = 9

The square of 9 is:  9² = 81.

5 times her actual age:  5 × 14 = 70

81 is 11 more than 70, hence verifying that her <u>actual age is 14 years old</u>.

Learn more about quadratic equations here:

brainly.com/question/27956741

brainly.com/question/27947331

5 0
1 year ago
Read 2 more answers
The probability of rain =0.2, sun=0.3,cloud=0.5. What is the probability of rain and sun over a two day period?
svp [43]

Answer:

0.2752512

Step-by-step explanation:

The formula you are looking for is the binomial probability:

               

                n!

P (X) = ------------    * (P)^X  * (q)^n - X

           (n- X)! X!    

For your particular problem:

n=7

X=2

 

q = 1-p = .8

7!/(5!*2!)*(.2)^2*(.8)^5 = 0.2752512

Hope this helps, have a nice day/night! :D

6 0
3 years ago
Which equation represents a line that passes through (2, –left-parenthesis 2, negative StartFraction one-half EndFraction right-
kompoz [17]

Answer:

16

Step-by-step explanation:

correct on Edg

7 0
3 years ago
Evan spent 15.89 on 7 pounds of birdseed how much did the bird seed cost per pound
Ugo [173]
Evan spent $2.27 on each pound of bird seed. To solve this divide the cost of the bird seeds by the pounds, which will lead you to this answer. Hope this helped! :)
8 0
3 years ago
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