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Annette [7]
3 years ago
12

Help!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Dvinal [7]3 years ago
8 0

Answer:

The Square root is 6/13

Step-by-step explanation:

You just have to find a number when multiplied by itself = the number you are given.

Like 6 x 6 =36

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What does n equal to in 12n + 9 = 6 - 3n
sveticcg [70]
12n+9=6-3n\ \ \ \ \ \ |Add\ 3n\ to\ each\ side\\\\
15n+9=6\ \ \ \ \ |Subtract\ 9\\\\
15n=-3\ \ \ \ \ |Divide\ by\ -15\\\\
n=-\frac{3}{15}=\boxed{-\frac{1}{5}}
6 0
3 years ago
How can polynomials be applied to financial situations?
Korvikt [17]
In financial<span> planning, </span>polynomials<span> are used to calculate interest rate problems that determine how much money a person accumulates after a given number of years with a specified initial investment.</span>
7 0
3 years ago
Read 2 more answers
Bailey has a video streaming service with a flat monthly fee of $18.00 plus an additional cost of $3.50 for each premium movie r
brilliants [131]

Answer:

3.50 x+18.00 ≤ 40.00

Step-by-step explanation:

She pays 18 dollars each moth, therefore that quantity won't change, so you will have to add. Each movie that she watches is an additional 3.50, then we have 3.50 x, x being the quantity of movies that she watches. She can only afford up to 40 dollars, then everything that she spends has to be less or equal to 40.

8 0
3 years ago
Read 2 more answers
Maria studied the traffic trends in India. She found that the number of cars on the road increases by 10% each year. If there we
lord [1]

Answer:

b. 8,800,000.

Step-by-step explanation:

In maria study the number of cars on the road increases by 10% each year.

Total number of cars in the first year =80 million cars.

We will add 10% of 80 million to 80 milion to enable us get the number of cars for the second year.

For year 2 we have;

10% of 80,000,000+80,000,000

\frac{10}{100}*80,000,000+80,000,000

8,000,000 + 80,000,000

88,000,000

number of cars in year 2 = 88 million

We will add 10% of 88 million to 88 milion to enable us get the number of cars for the third year.

\frac{10}{100}*88,000,000+88,000,000

8,800,000+88,000,000

96,800,000

the number of cars on the road in year 3 compared to year 2 will just be the increase which is in BOLD. That is 8,800,000

<em>or simply subtract the number of cars in year 2 from that in year 3;</em>

96,800,000-88,000,000 = 8,800,000

8 0
4 years ago
Read 2 more answers
HELPPPP will mark brainliest
ArbitrLikvidat [17]

Answer:

12x-2

Step-by-step explanation:

You need to add 5x+1 and 7x-3.

5x+1+7x-3.

We need to organize this into common terms.

5x+7x+1-3

Now we simplify.

12x-2

That is the final answer!!

Hope this helped!!!! :D

6 0
3 years ago
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