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stellarik [79]
3 years ago
7

A radiator contains 8 quarts of fluid, 40% of which is antifreeze. How much fluid should be drained and replaced with pure antif

reeze so that the new mixture is 60% antifreeze? pls help i have an important test
Mathematics
1 answer:
ICE Princess25 [194]3 years ago
8 0

Answer:

Step-by-step explanation:

<u><em>JeanaShupp   </em></u>                 <- he has                               the answer thank him

Ace                                                              

10.2K answers

87.3M people helped

Answer: 1.6 quarts

Step-by-step explanation:

Given : A radiator contains 8 quarts of fluid, 40% of which is antifreeze.

[40% can be written as 0.40.]

Then, the amount of antifreeze in radiator =                                                                                               (1)

If a radiator contains 8 quarts of fluid with 60% of which is antifreeze.

[60% can be written as 0.60.]

Then, the amount of antifreeze in radiator =                                                                                              (2)

Now subtract (1) from (2) we get,

The amount of fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze :-

Hence, the 1.6 quarts of fluid should be drained  and replaced with pure antifreeze so that the new mixture is 60% antifreeze

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