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3 years ago

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A radiator contains 8 quarts of fluid, 40% of which is antifreeze. How much fluid should be drained and replaced with pure antif

reeze so that the new mixture is 60% antifreeze? pls help i have an important test

1 answer:

ICE Princess25 [194]3 years ago

8 0

Answer:

Step-by-step explanation:

<u><em>JeanaShupp </em></u> <- he has the answer thank him

Ace

10.2K answers

87.3M people helped

Answer: 1.6 quarts

Step-by-step explanation:

Given : A radiator contains 8 quarts of fluid, 40% of which is antifreeze.

[40% can be written as 0.40.]

Then, the amount of antifreeze in radiator = (1)

If a radiator contains 8 quarts of fluid with 60% of which is antifreeze.

[60% can be written as 0.60.]

Then, the amount of antifreeze in radiator = (2)

Now subtract (1) from (2) we get,

The amount of fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze :-

Hence, the 1.6 quarts of fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze

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Answer:

C. $t=23,r=9$ .

Step-by-step explanation:

Let r represent the cost of one packet of radish seeds and let t represent the cost of one packet of tomato seeds.

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Using guess and check means we substitute into the given equation.

A) We substitute $t=8,r=24$ into both equations.

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B)

We substitute $t=9,r=23$ into both equations.

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We substitute $t=23,r=9$ into both equations.

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Answer:

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Step-by-step explanation:

Data provided in the question:

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The pooled variance is calculated using the formula,

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