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Mars2501 [29]
3 years ago
5

For which function is f(x) equal to f1 (x) ? PLEASE HELP;)

Mathematics
1 answer:
gregori [183]3 years ago
5 0
The answer for your problem is B
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If fx = 2x^2 + 3 and g(x) = x^2 - 7 find (f - g) (x)
Semmy [17]

(f-g) (x) means to subtract g(x) from f(x)

F(x) = 2x^2 +3

g(x) = x^2

This becomes:

2x^2 + 3 - x^2 = x^2 +3

3 0
3 years ago
How do you factor -6a+27b-15c
tatyana61 [14]


-3 (2a-9b+5c)

common factor out the lowest common factor which is -3

5 0
3 years ago
Evaluate the numerical expression<br> [18 Divided by (2 x 3)] x 4
Nastasia [14]
P: parenthesis
E: exponents
MD: multiplication or division (whichever comes first left to right)
AS: addition or subtraction (whichever comes first left to right)

This is the order of operations. We will use this to solve the equation correctly.
We will start with the parenthesis. 2x3=6.
[18/6]x4
Next, we will do the rest of the parenthesis.
18/6=3.
This gets rid of the parenthesis (or brackets.) We will now do the rest of the problem, which is multiplying 3 and 4.
3x4=12.
12 is your final answer.
6 0
3 years ago
Algebra 2 need help on a ( ABC )
Len [333]

Answer:

b)

x =  \frac{15}{4}

Step-by-step explanation:

b) set up equations so they are equal to each other,

2x - 2 =  - 3x + 12

5x = 14

x = \frac{14}{5}

this is when f(x)=g(x) so our approximation was close.

c)solving it graphically is nearly impossible because the solution can be any value around the intersection. only way to be sure is to solve it symbolically.

3 0
3 years ago
The three angle bisectors of ΔABC intersect at point P. Point P is the
lisabon 2012 [21]
<h3>Answer: C) incenter</h3>

========================================

Explanation:

If you were to intersect the angle bisectors (at least two of them), then you would locate the incenter. The incenter is the center of the incircle which is a circle where it is as large as possible, but does not spill over and outside the triangle. Therefore this circle fits snugly inside the triangle.

--------------

extra notes:

* The centroid is found by intersecting at least two median lines

* The circumcenter is found by intersecting at least two perpendicular bisector lines

* The orthocenter is found by intersecting at least two altitude lines

* The incenter is always inside the triangle; hence the "in" as part of the name. The centroid shares this property as well because the medians are completely contained within any triangle. The other two centers aren't always guaranteed to be inside the triangle.

* The red lines cut each angle of the triangle into two equal or congruent pieces.

5 0
3 years ago
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