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3 years ago

Marissa is painting her rectangular patio, with the exception of a bench that does not need to be painted:

Mathematics

1 answer:

kirill115 [55]3 years ago

7 0

Answer:

A = (x + 25)(x + 15) - 30

Step-by-step explanation:

This question is not complete without a figure; find the figure attached.

Marissa is painting a regular patio with dimensions as

Length = (x + 25) units

Width = (x + 15) units

Area of this rectangular patio = Length × Width

Area = (x + 25)(x + 15) unit²

She has to paint the patio except the bench that does not need to be painted.

Dimensions of the rectangular bench,

Length = 10 units

Width = 3 units

Area of the bench = 10×3 = 30 units²

Area of the patio to be painted = Area of patio - Area of bench

A = (x + 25)(x + 15) - 30

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Form a polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3

polet [3.4K]

The polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3 is $x^3-3x^2-x+3=0$

Step-by-step explanation:

We need to find a polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3.

If -1, 1 and 3 are real zeros, it can be written as:

x= -1, x= 1, and x = 3

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Finding polynomial by multiply these factors:

$(x+1)(x-1)(x-3)=0\\(x+1)(x(x-3)-1(x-3))=0\\(x+1)(x^2-3x-x+3)=0\\(x+1)(x^2-4x+3)=0\\x(x^2-4x+3)+1(x^2-4x+3)=0\\x^3-4x^2+3x+x^2-4x+3=0\\Combining\,\,like\,\,terms:\\x^3-4x^2+x^2+3x-4x+3=0\\x^3-3x^2-x+3=0$

So, The polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3 is $x^3-3x^2-x+3=0$

Keywords: Real zeros of Polynomials

Learn more about Real zeros of Polynomials at:

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