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2 years ago

Please help I’ll give Brainly I need help please please please please

Mathematics

2 answers:

Step2247 [10]2 years ago

3 0

Answer:

1.8 is correct

Step-by-step explanation:

You can use Desmos for future advice

Ira Lisetskai [31]2 years ago

3 0

Helloo,
The answer is 1.8!
Pleaseeee mark as brainliest

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2. About how much is 123.1 do you weigh in pounds? Estimate if you don't know☺ Find an online converter and find out how many ki

Mama L [17]

Answer:

123.1 pounds is vary long, and I don't want to repeat, so 55.8372207 repeat.

Step-by-step explanation:

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2 years ago

True or False: You can tell if two ratios form a proportion if their cross products are equal. True O False

daser333 [38]

Answer:

Step-by-step explanation:

False

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2 years ago

Idently the graph of f(x) = 3(x - 1) - 4. Then identity the vertex and ads of symmetry find the minimum value of and describe wh

Vesna [10]

Answer:

See below

Step-by-step explanation:

I assume you mean $f(x) = 3(x-1)^2-4$

The equation is already in vertex form $f(x)=a(x-h)^2+k$ where $a$ affects how "fat" or "skinny" the parabola is and $(h,k)$ is the vertex. Therefore, the vertex is $(h,k)\rightarrow(1,-4)$ .

The axis of symmetry is a line where the parabola is cut into two congruent halves. This is defined as $x=h$ for a parabola with a vertical axis. Hence, the axis of symmetry is $x=1$ .

The minimum value is the smallest value in the range of the function. In the case of a parabola, the y-coordinate of the vertex is the minimum value. Therefore, the minimum value is $y=-4$ .

The interval where the function is decreasing is $(-\infty,1)$

The interval where the function is increasing is $(1,\infty)$

8 0

2 years ago

Why do we need to find the average of something

daser333 [38]

Answer:

To know what is the average of it

Step-by-step explanation:

7 0

3 years ago

I NEED HELP PLEASE, THANKS! :)

Elena L [17]

Answer:

First option is the right choice.

Step-by-step explanation:

$\frac{1}{\cos \left(x\right)+1}+\frac{1}{\cos \left(x\right)-1}\\\\\frac{\cos \left(x\right)-1}{\left(\cos \left(x\right)+1\right)\left(\cos \left(x\right)-1\right)}+\frac{\cos \left(x\right)+1}{\left(\cos \left(x\right)+1\right)\left(\cos \left(x\right)-1\right)}\\\\=\frac{\cos \left(x\right)-1+\cos \left(x\right)+1}{\left(\cos \left(x\right)+1\right)\left(\cos \left(x\right)-1\right)}\\\\=\frac{2cos\left(x\right)}{cos^2\left(x\right)-1}\\\\=\frac{2cos\left(x\right)}{sin^2\left(x\right)}$

$=2\cdot \frac{cos\left(x\right)}{sin\left(x\right)}\cdot \frac{1}{sin\left(x\right)}\\\\=-2cot(x)csc(x)$

Best Regards!

7 0

3 years ago