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2 years ago

Can you help me find the measure of angle B plss

Mathematics

1 answer:

wariber [46]2 years ago

4 0

Angie B is 128 degrees. Because this is a supplementary angle you can find the unknown value by subtracting 52 from 180

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What is the area of this trapezoid? Enter your answer in the box.

Anton [14]

Answer:

Step-by-step explanation:

5 0

2 years ago

Use the graph below to determine a1 and d for the sequence. graphed sequence showing point 1, negative 10, point 2, negative 7,

Sonja [21]

Answer:

$a_1=-10$

$d=3$

Step-by-step explanation:

we know that

In an Arithmetic Sequence the difference between one term and the next is a constant, and this constant is called the common difference (d)

In this problem we have the ordered pairs

$(1,-10),(2,-7),(3,-4),(4,-1),(5,2),(6,5)$

Let

$a_1=-10\\a_2=-7\\a_3=-4\\a_4=-1\\a_5=2\\a_6=5$

Find the difference between one term and the next

$a_2-a_1=-7-(-10)=3$

$a_3-a_2=-4-(-7)=3$

$a_4-a_3=-1-(-4)=3$

$a_5-a_4=2-(-1)=3$

$a_6-a_5=5-2=3$

The difference between one term and the next is a constant

This constant is the common difference

The sequence graphed is an Arithmetic Sequence

therefore

The first term is $a_1=-10$

The common difference is equal to $d=3$

4 0

2 years ago

You start with a penny which doubles each day for 30 days. How much money would you have after 30 days?

Radda [10]

Answer:

$555,765.76

Step-by-step explanation:

128

256

512

1024

2048

4096

8192

16282

32564

65128

13256

26512

53024

106048

212096

424192

868384

1736768

3473536

6947072

13894144

27788288

55576576=

555,765.76

6 0

2 years ago

Bella earned the federal minimum wage in the year 2008. During that time, she worked 37.5 hours per week. How much money did she

Mariana [72]

Answer:

Belle's weekly earnings per week in 2008: $245.7

Step-by-step explanation:

The federal minimum wage in the year 2008 was: $6.55

She worked 37.5 hours per week.

She earn each week:

$weekly earnings = 6.55*37.5=245.7$

7 0

2 years ago

Read 2 more answers

Find the slope-intercept form of the equation of the line passing through the given points.

Ugo [173]

$The\ slope-intercept\ form:y=mx+b\\\\The\ slope-point\ form:y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}$

$(1;\ 1)\to x_1=1;\ y_1=1\\\left(3;-\dfrac{1}{5}\right)\to x_2=3;\ y_2=-\dfrac{1}{5}.\\\\Subtitute:\\\\m=\dfrac{-\frac{1}{5}-1}{3-1}=\dfrac{-1\frac{1}{5}}{2}=-\dfrac{\frac{6}{5}}{2}=-\dfrac{\not6^3}{5}\cdot\dfrac{1}{\not2_1}=-\dfrac{3}{5}$

$y-1=-\dfrac{3}{5}\left(x-1\right)\\\\y-1=-\dfrac{3}{5}x+\dfrac{3}{5}\ \ \ \ |add\ 1\ to\ both\ sides\\\\\boxed{y=-\frac{3}{5}x+1\frac{3}{5}}$

5 0

3 years ago