Answer:
2/10
Step-by-step explanation:
Probability of getting head on i'th coin = i/10
Probability Pr of getting head on 2nd coin (Event A) = 2 / 10
Probability Pr of getting head on 1st coin (Event B) = 1/10
Probability A given B = Pr (A/B) = Pr (A∩B) / Pr B ;
where A∩B = Pr (A & B) = Pr A X Pr B
Putting in above formula :
Pr (A/B) = <u>[(</u>1/10)x(2/10<u>)]</u> / 1/10
= 2/10
X + 5y = 6
5y = -x + 6
y = -1/5x + 6/5....the slope here is -1/5. A perpendicular line will have a negative reciprocal slope. All that means is flip the original slope and change the sign. So we flip -1/5 and make is -5/1....and we change the sign...making it 5/1 or just 5. So our perpendicular line will have a slope of 5.
y = mx + b
slope(m) = 5
(2,-2)...x = 2 and y = -2
sub and find b, the y int
-2 = 5(2) + b
-2 = 10 + b
-2 - 10 = b
-12 = b
so ur perpendicular equation is : y = 5x - 12 <=
Step-by-step explanation: Using the equation, y = mx + b, the slope-intercept form, plug in the values you have and solve for b. (m is the slope.) You have y = -8 and x = 4 and m = 1/2.
3/4 times x=2
times both sides by 4/3 to clear fraction (4/3 times 3/4=12/12=1)
1x=8/3
there are 8/3 of them in 2
We have (3/4)^2 + (
/4)^2 = 9/16 + 7/16 = (9+7)/16 = 16/16 = 1.
The answer is yes.
