At basketball practice you make 21 shots out of 80. What is the closest percent to the shot you made

What is the equation of a line with a slope of -2 that passes through the point (-2,12)?

slavikrds [6]

Answer:

y=-2x + 8 which is the required equation

Which is option C

Step-by-step explanation:

Given:

Slope = m = -2

Given points are ( -2,12)

Which is

x = -2 and y =12

TO find:

Equation of line passing through these points = ?

Solution:

The point slope form of a line is

y = mx + c

Here we don't know the value of c

To find it

Putting y = 12 , x= -2 and y = -2 in the given equation

y = mx + c

Putting values it becomes

12 = (-2)*(-2) + c

12 = 4 + c

Subtracting 4 from both sides

12-4 = 4 -4 + c

8 = c

Now we have

m = -2 and c= 8

So equation of a line is given by

y = mx + c

Putting value of m and c

y = -2*x + 8

y=-2x + 8 which is the required equation

7 0

2 years ago

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Janice is roller skating at a constant speed away from her house. The first half of the street is flat, but the second half has

Zolol [24]

Answer:

It's Z.

Step-by-step explanation:

Because the road is straight at first, then it gets steep.

which means that the road goes down,

kinda like a drop off.

8 0

3 years ago

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the average waiting time to be seated for dinner at a popular restaurant is 23.5 minutes with a standard deviation of 3.6 minute

creativ13 [48]

Look it up on google

5 0

3 years ago

Which of the following ordered pairs could be placed in the table and still have the relation qualify as a linear function? (4 p

Lerok [7]

Answer:

(2, 7)

Step-by-step explanation:

7 0

2 years ago

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Find the general solution of the differential equation and check the result by differentiation. (Use C for the constant of integ

atroni [7]

Answer: $y=Ce^(^3^t^{^9}^)$

Step-by-step explanation:

Beginning with the first differential equation:

$\frac{dy}{dt} =27t^8y$

This differential equation is denoted as a separable differential equation due to us having the ability to separate the variables. Divide both sides by 'y' to get:

$\frac{1}{y} \frac{dy}{dt} =27t^8$

Multiply both sides by 'dt' to get:

$\frac{1}{y}dy =27t^8dt$

Integrate both sides. Both sides will produce an integration constant, but I will merge them together into a single integration constant on the right side:

$\int\limits {\frac{1}{y} } \, dy=\int\limits {27t^8} \, dt$

$ln(y)=27(\frac{1}{9} t^9)+C$

$ln(y)=3t^9+C$

We want to cancel the natural log in order to isolate our function 'y'. We can do this by using 'e' since it is the inverse of the natural log:

$e^l^n^(^y^)=e^(^3^t^{^9} ^+^C^)$

$y=e^(^3^t^{^9} ^+^C^)$

We can take out the 'C' of the exponential using a rule of exponents. Addition in an exponent can be broken up into a product of their bases:

$y=e^(^3^t^{^9}^)e^C$

The term e^C is just another constant, so with impunity, I can absorb everything into a single constant:

$y=Ce^(^3^t^{^9}^)$

To check the answer by differentiation, you require the chain rule. Differentiating an exponential gives back the exponential, but you must multiply by the derivative of the inside. We get:

$\frac{d}{dx} (y)=\frac{d}{dx}(Ce^(^3^t^{^9}^))$

$\frac{dy}{dx} =(Ce^(^3^t^{^9}^))*\frac{d}{dx}(3t^9)$

$\frac{dy}{dx} =(Ce^(^3^t^{^9}^))*27t^8$

Now check if the derivative equals the right side of the original differential equation:

$(Ce^(^3^t^{^9}^))*27t^8=27t^8*y(t)$

$Ce^(^3^t^{^9}^)*27t^8=27t^8*Ce^(^3^t^{^9}^)$

QED

I unfortunately do not have enough room for your second question. It is the exact same type of differential equation as the one solved above. The only difference is the fractional exponent, which would make the problem slightly more involved. If you ask your second question again on a different problem, I'd be glad to help you solve it.

7 0

2 years ago