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3 years ago

7

At basketball practice you make 21 shots out of 80. What is the closest percent to the shot you made

1 answer:

patriot [66]3 years ago

7 0

$\frac{21}{80} \times 100 = 26.25$
So the closest shot u made is 27%

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Find the surface area of the prism. Length: 5 width: 8 height: 12 in

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3 years ago

Simplify the expression. 7 √x • 7 √x • 7 √x

blsea [12.9K]

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√7x−49√x

Explanation:

First of all, expand by multiplying √7x⋅√x and √7x⋅7√7respectively:

√7x(√x−7√7)=√7x⋅√x−√7x⋅7√7

... you can express √7x as √7⋅√x...

=√7⋅√x⋅√x−√7⋅√x⋅7⋅√7

=√7⋅(√x)2−(√7)2⋅√x⋅7

... the operations squaring and taking the square root "eliminate each other"...

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=√7x−49√x

Hope that this helped!

8 0

3 years ago

we believe that 42% of freshmen do not visit their counselors regularly. For this year, you would like to obtain a new sample to

Maksim231197 [3]

Answer:

A sample of 1077 is required.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

42% of freshmen do not visit their counselors regularly.

This means that $\pi = 0.42$

98% confidence level

So $\alpha = 0.02$ , z is the value of Z that has a pvalue of $1 - \frac{0.02}{2} = 0.99$ , so $Z = 2.327$ .

How large of a sample size is required?

A sample size of n is required, and n is found when M = 0.035. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.035 = 2.327\sqrt{\frac{0.42*0.58}{n}}$

$0.035\sqrt{n} = 2.327\sqrt{0.42*0.58}$

$\sqrt{n} = \frac{2.327\sqrt{0.42*0.58}}{0.035}$

$(\sqrt{n})^2 = (\frac{2.327\sqrt{0.42*0.58}}{0.035})^2$

$n = 1076.8$

Rounding up:

A sample of 1077 is required.

3 0

3 years ago