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nikitadnepr [17]
3 years ago
7

Find AB using the given matrices.

Mathematics
1 answer:
solniwko [45]3 years ago
5 0

The entry in row 1, column 1 of \mathbf{AB} is

\begin{bmatrix}2&4\end{bmatrix}\begin{bmatrix}5\\6\end{bmatrix}=2\cdot5+4\cdot6=34

(i.e. the dot product of row 1 of \mathbf A and column 1 of \mathbf B)

The entry in row 1, column 2 of \mathbf{AB} is

\begin{bmatrix}2&4\end{bmatrix}\begin{bmatrix}-9\\-4\end{bmatrix}=2\cdot(-9)+4\cdot(-4)=-34

The second option is the correct answer.

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Part 1) <span>Given the two points (-24,7) and (30,25) a. What is an equation passing through the points?

step 1
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m=(y2-y1)/(x2-x1)----></span>m=(25-7)/(30+24)----> m=18/54----> m=1/3

step 2
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the answer Part 1) is
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Part 2) <span>Is (51, 33) also on the same line?
</span>if the point (51.33) is on the line y=(1/3)*x+15
then
for x=51 the value of y must be 33
for x=51
y=(1/3)*51+15----> y=17+15----> y=32
32 is not 33 
so
<span>the point does not belong to the given line
</span>
the answer Part 2) is
the point does not belong to the given line

see the attached figure

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Answer:

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