A circle will always add up to 360 degrees
so the equation is
(13x+2)+(5x+24)+(7x+7)+(8x-3)=360
We want to isolate x, so first we must combine like terms, the equation is now
33x+30=360
We will then subtract 30 from both sides, leaving the equation as
33x=330
Next we will divide each side by 33
33x/33=x
330/33=10
So x=10
We'll then plug this into the equation section to solve for JNK
So 5x+24
Plug in the 10 into the x value, and the equation is now
5(10)+24
5*10=50 So the equation is now
50+24
50+24=74
So angle JNK is equal to 74 degrees
So your answer is C
Answer:
y^1/4
Step-by-step explanation:
when you want to make the negative exponent positive, flip over the fraction to (y^1/4)/1. The one ovi doesn't have to be there, so just y^1/4.
Answer:
i think it is C
Step-by-step explanation:
Answer:
t = 3.5 sec
Step-by-step explanation:
The equation that represents the position of the ball as a function of time is the following:
Where:
= Initial position of the ball (4 feet tall)
= Initial speed of the ball (55feet / s)
a = acceleration (9.8
, or in this case 32.16
)
t = time in seconds
Then we want to know how long it takes to get to the ground, for this we equal h (t) = 0 and clear t.
So:
![0 = 4 + 55t -16.08t ^ 2](https://tex.z-dn.net/?f=0%20%3D%204%20%2B%2055t%20-16.08t%20%5E%202)
Solving the second degree equation we have:
![\frac{-55+\sqrt{55^2-4 (-16.08) 4}}{2 (-16.08)}= -0.0712\\\frac{-55-\sqrt{55^2-4 (-16.08) 4}}{2 (-16.08)} = 3.492](https://tex.z-dn.net/?f=%5Cfrac%7B-55%2B%5Csqrt%7B55%5E2-4%20%28-16.08%29%204%7D%7D%7B2%20%28-16.08%29%7D%3D%20-0.0712%5C%5C%5Cfrac%7B-55-%5Csqrt%7B55%5E2-4%20%28-16.08%29%204%7D%7D%7B2%20%28-16.08%29%7D%20%3D%203.492)
t = -0.071 sec
t = 3.5 sec
We must take the positive solution.
So:
t = 3.5 sec
The line intercepts the y axis which is up and down at the point -1