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Tems11 [23]
3 years ago
15

In sunlight, a vertical stick 7 ft tall casts a shadow 3 ft long. At the same time a nearby tree casts a shadow 11 ft long. How

tall is the tree? Round to the nearest tenth.

Mathematics
2 answers:
Leviafan [203]3 years ago
6 0
look\ at\ the\ picture\\\\\Delta ABC\sim\Delta D EF\\\\\frac{|ED|}{|EF|}=\frac{|AB|}{|BC|}\\\\\frac{|ED|}{11}=\frac{7}{3}\ \ \ \ /\cdot11\\\\|ED|=\frac{77}{3}\\\\|ED|\approx25.7\ (ft)\leftarrow Answer

oksian1 [2.3K]3 years ago
4 0

Answer:

25.7 feet.

Step-by-step explanation:

Let x be the actual length of tree.

We have been given that in sunlight, a vertical stick 7 ft tall casts a shadow 3 ft long. We are asked to find the actual length of tree casting a 11 ft long shadow.

We will use proportions to solve our given problem.

\frac{x}{11}=\frac{7}{3}

Upon multiplying both sides of our equation by 11, we will get:

\frac{x}{11}*11=\frac{7}{3}*11

x=\frac{77}{3}

x=25.6666666\approx 25.7

Therefore, the tree is 25.7 feet tall.

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8. Terry drove 366 miles in 6 hours at a
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Read 2 more answers
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The difference is  $\frac{3 x+81}{x(x-9)(x+9)}$

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Removing the parenthesis, we have,

$\left\frac{9}{x^{2}-9 x}\right-\left\frac{6}{x^{2}-81}\right$

Factoring the terms $x^{2}-9 x$ and $x^{2}-81$, we get,

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Taking LCM, we get,

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Simplifying the numerator, we get,

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Subtracting the numerator, we have,

$\frac{3 x+81}{x(x-9)(x+9)}$

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