A force of 4.05×10⁶ N was exerted on one side of the wall.
<h3>What is the force?</h3>
Force is an external agent capable of changing the state of rest or motion of a particular body. It has a magnitude and a direction.
The following data were obtained from the question:
Breadth (B) = 4 m
Length (L) = 10 m
Standard pressure (P) = 101325 Nm¯²
Next, we shall determine the area of the wall. This can be obtained as follow:
Area (A) = length (L) × breadth (B)
A = 10 × 4
A = 40 m²
Finally, we shall determine the force exerted on one side of the wall as follow:
Standard pressure (P) = 101325 Nm¯²
Area (A) = 40 m²
Pressure (P) = Force (F) /Area (A)
101325 = F/40
F = 101325 × 40
F = 4.05×10⁶ N.
Therefore, a force of 4.05×10⁶ N was exerted on one side of the wall.
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Answer:
m∠1=111°
Step-by-step explanation:
Since angle 1 is an exterior angle on a straight line, it is the sum of the two outer angles of the triangle.
64+47=111.
Answer:
90%, or 180%, it depends on if one rectangle equals one whole, if yes, then 180%, but if both rectangles equal one whole then 90%
Isolate the variable by dividing each side by factors that don't contain the variable.
Inequality Form:
b
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4.541
¯
6
b
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Interval Notation:
(
−
∞
,
4.541
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First of all, to simplify expressions we use the PEMDAS
then we do the right needed inverse to move the variables all to one side and the other numbers to another... this is a way we simplify expressions
Hope this helps :)
