Can someone please help me with this its urgent I don’t get it
1 answer:
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Answer:
The 95 % confidence interval for the mean is between 28.09 and 35.97.
Step-by-step explanation:
Mean of the sample:
30 values.
So we sum all the values and divide by 30.
The sum of all the values(43 + 52 + 18 + ... + 20 + 41) is 961.
961/30 = 32.03
Confidence interval:
We have that to find our level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of .
So it is z with a pvalue of , so
Now, find the margin of error M as such
In which is the standard deviation of the population and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 32.03 - 3.94 = 28.09
The upper end of the interval is the sample mean added to M. So it is 32.03 + 3.94 = 35.97
The 95 % confidence interval for the mean is between 28.09 and 35.97.