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slavikrds [6]
3 years ago
8

What is the interquartile of 44, 51, 56, 73, 81?

Mathematics
1 answer:
Finger [1]3 years ago
7 0

Answer: 29.5

Step-by-step explanation:

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Find the 50th term of this arithmetic sequence:<br><br> 6, 13, 20, 27, . . .<br><br> Answer:
valkas [14]

Answer:

346380

Step-by-step explanation:

hope you gwt an a

7 0
2 years ago
Can someone help me find the volume of this?
GalinKa [24]
To find the volume of any cube you need to know the length, width and height. The formula to find the volume multiplies the length by the width by the height. The good news for a cube is that the measure of each of these dimensions is exactly the same. Therefore, you can multiply the length of any side three times.
5 0
3 years ago
Find two consecutive integers such that one fifth of the first less one-ninth of the second is 3. Pls answer.​
mart [117]

Answer:

35 and 36

Step-by-step explanation:

To solve this problem, we must interpret it line by line;

  • We are dealing with consecutive integers; these are integers with a difference of 1 between them.

   let the first number = x

               second number  = x + 1

  • one - fifth of first;

             \frac{1}{5}x

  •   one - ninth of the second;

            \frac{1}{9}(x + 1)

for the "less" ;

         \frac{1}{5}x -  \frac{1}{9}(x + 1) = 3

Multiply through by 45

       45(\frac{1}{5}x) - (45) \frac{1}{9}(x + 1) = 3 x 45

           9x - 5(x + 1) = 135

           9x - 5x -5 = 135

             4x = 135 + 5

              4x = 140

                x = 35

Now, x+1  = 35 + 1 = 36

The consecutive integers are 35 and 36

4 0
3 years ago
Why is 6/11=x/33 not a proportion
sertanlavr [38]

6/11=x/33 is not a proportion because they aren't equal to each other.

6 0
3 years ago
Arrange the entries of matrix A in increasing order of their cofactors values
givi [52]

To find the cofactor of

A=\left[\begin{array}{ccc}7&5&3\\-7&4&-1\\-8&2&1\end{array}\right]

We cross out the Row and columns of the respective entries and find the determinant of the remaining 2\times 2 matrix with the alternating signs.


Ac_{11}=\left|\begin{array}{ccc}4&-1\\2&1\end{array}\right|


Ac_{11}=4\times 1- -1\times 2


Ac_{11}=4+ 2

Ac_{11}=6




Ac_{12}=-\left|\begin{array}{ccc}-7&-1\\-8&1\end{array}\right|


Ac_{12}=-(-7\times 1- -1\times -8)


Ac_{12}=-(-7- 8)

Ac_{12}=15




Ac_{21}=-\left|\begin{array}{ccc}5&3\\2&1\end{array}\right|


Ac_{21}=-(5\times 1- 3\times 2)


Ac_{21}=-(5-6)


Ac_{21}=1







A_c{23}=-\left|\begin{array}{ccc}7&5\\-8&2\end{array}\right|


Ac_{23}=-(7\times 2 -8\times 5)


Ac_{23}=-(14-40)


Ac_{23}=26




A_c{31}=\left|\begin{array}{ccc}5&3\\4&-1\end{array}\right|


Ac_{31}=5\times -1 -4\times 3


Ac_{31}=-5-12


Ac_{31}=-17


A_c{33}=\left|\begin{array}{ccc}7&5\\-7&4\end{array}\right|


Ac_{33}=7\times 4- -7\times 5


Ac_{33}=28+35


Ac_{33}=63


Therefore in increasing order, we have;

Ac_{31}=-17,Ac_{21}=1,Ac_{11}=6,Ac_{23}=26,Ac_{12}=15, Ac_{33}=63



7 0
3 years ago
Read 2 more answers
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