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Archy [21]
3 years ago
6

ABCD is a rectangle on a coordinate grid with side AB parallel to side CD and side BC parallel to side AD. If the slope of side

AB is 2/7, what is the slope of side BC?
Mathematics
2 answers:
fiasKO [112]3 years ago
8 0

Answer:

<h2>The slope of BC is -7/2.</h2>

Step-by-step explanation:

<h3>Givens</h3>

ABCD is a rectangle.

AB \parallel CD

BC \parallel AD.

m_{AB} =\frac{2}{7}

We know that AB \perp BC and CD \perp AD, by definition of rectangle.

Additionally, m_{AB} \times m_{BC}=-1, by condition of perpendicularity.

Replacing, we have

\frac{2}{7}  \times m_{BC}=-1\\ m_{BC}=-\frac{7}{2}

Therefore, the slope of BC is -7/2.

sashaice [31]3 years ago
4 0
The answer would be 2/7
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3 years ago
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Kryger [21]

Answer:

The answer is R

Explanation:

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Hope it helps!

4 0
3 years ago
3/4(x + 3) = 9<br><br><br> How do I solve this
Sonbull [250]

Answer:

x = 10

Step-by-step explanation:

so first distribute the 3/4 to everything on the inside

3/4x + 1 1/2 = 9

now subtract 1 1/2 on both sides

3/4x = 7 1/2

Now divide both sides by 3/4

x = 7 1/2 divided by 3/4

x = 15/2 divided by 3/4

x = 15/2 times 4/3

x = 5/1 times 2/1

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4 0
2 years ago
For A (1, –1), B (–1, 3), and C (4, –1), find a possible location of a fourth point, D, so that a parallelogram is formed using
katrin [286]

The possible coordinates for the vertex D of the parallelogram could be (-4, 3)

It is given that A(1, –1), B (–1, 3), and C (4, –1) are the three vertices of the parallelogram.

Let us assume that the vertices are in the order A, C, B, and D where the coordinates of D are (a, b).

In this scenario, if we join AB and CD, they will become the diagonals of the parallelogram ABCD.

According to the properties of a parallelogram, diagonals bisect each other.

Hence, mid-point of AB = mid-point of CD

Now, according to the mid-point theorem, if mid-point of AB is given as (x,y), then,

x = (x₁ + x₂)/2 and y = (y₁ + y₂)/2

Here, for AC,

x₁ = 1, y₁ = -1

x₂ = -1, y₂ = 3

Then, x = ( 1 - 1)/2 and y = (-1 + 3)/2

(x, y) ≡ (0, 1)  ............. (1)

Since (x, y) is also the mid-point of CD, we also have,

x₁ = 4, y₁ = -1

x₂ = a, y₂ = b

Then, x = (4 + a)/2 and y = (-1 + b)/2

(x, y) ≡ ((4 + a)/2, (-1 + b)/2) ................... (2)

From (1) and (2),

(4+a)/2 = 0 and (-1+b)/2 = 1

4+a = 0 and (-1+b) = 2

a = -4 and b = 3

Hence, the fourth vertex D of the parallelogram can be possibly located at (-4, 3)

Learn more about a parallelogram here:

brainly.com/question/1563728

#SPJ1

8 0
2 years ago
Please help me 25 points and the best answer will be marked as brainliest
Zanzabum
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