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Sliva [168]
3 years ago
14

A line passes through the point (1,4) and is perpendicular to the line with equations y=-1/5x+2. what's the equation of the line

?
Mathematics
1 answer:
jekas [21]3 years ago
4 0

To find the slope of the perpendicular line, you can take the negative reciprocal of the slope of the line it is perpendicular to.

Taking the negative reciprocal of -1/5 gives 5.

Now we have y=5x+b, where b is the y-intercept. Since we know that the perpendicular line passes through the point (1,4), we can substitute those values into the equation we have to find b.

y=5x+b

4=5(1)+b

4=5+b

b=-1

Therefore, the equation of the perpendicular line is y=5x-1.

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The perimeter of a triangle is 56. The side lengths are x + 4, 3x + 7, and x + 9. What is the value of x?
Sidana [21]
<h3><u>Answer:</u></h3>
  • x = 7.2
<h3><u>Step-by-step explanation:</u></h3>
  • Perimeter: Side 1 + Side 2 + Side 3
  • => x + 4 + 3x + 7 + x + 9 = 56
  • => 5x + 20 = 56
  • => 5x = 56 - 20
  • => 5x = 36
  • => x = 7.2
<h3><u>Conclusion:</u></h3>

Therefore, the value of x is 7.2.

Hoped this helped.

BrainiacUser1357

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3 years ago
HELP!!! It’s due is 20 minutes
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ivanzaharov [21]

Answer:

Step 1: Multiply 1x5 Step 2: Multiply 2x3 Step 3: Add the two products

d=v*t

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t=time

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What is the length of the diagonal of a cube with a side length of 5 cm? Round to the nearest tenth. 7.1 cm 8.7 cm 21.3 cm 26.7
sesenic [268]
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6 0
3 years ago
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Two circles, one of radius 5 inches, the other of radius 2 inches, are tangent at point P. Two bugs start crawling at the same t
lawyer [7]

Answer:

  40 minutes

Step-by-step explanation:

The circumference of the larger circle is ...

  C = 2πr = 2π(5 in) = 10π in

The bug navigates the circumference at 3π in/min, so will take

  time = distance/speed = (10π in)/(3π in/min) = 10/3 min

to travel once around.

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The circumference of the smaller circle is ...

  C = 2πr = 2π(2 in) = 4π in

The bug navigates this circumference at 2.5π in/min, so will take

  (4π in)/(2.5π in/min) = 8/5 min

to travel once around.

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The bugs will meet at a time that is the least common multiple of these times. Both can be expressed in 15ths of a minute as ...

  {50/15, 24/15}

Then the LCM of these will be ...

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It will be 40 minutes before the bugs next meet at point P.

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A graphing calculator can make use of the mod function to show when the bugs meet at point P (total is displacement of the two bugs from P is zero). It shows the meeting occurs after 40 minutes.

5 0
4 years ago
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