Hello there.
6(8 - 2y) = 4y
To solve for this, we need to apply the Distributive Property to the left side of the equation. This property allows us to multiply the number outside of the parenthesis by all numbers inside of the parenthesis.
6(8 - 2y)
6(8) + 6(-2y)
48 - 12y
Now, let’s take a look at our equation.
-12y + 48 = 4y
To make things more simple, we’ll add 12y to both sides of the equation. This will cancel out -12y on the left side of the equation and will turn 4y on the right side of the equation into 16y.
Our new equation is:
16y = 48
Now all we need to do is divide both sides by 16 to solve for y.
16y / 16 = y
48 / 16 = 3
Our final answer and solution is:
Y = 3
I hope this helps!
A 12-sided die is rolled. The set of equally likely outcomes is {1,2,3,4,5,6,7,8,9,10,11,12}. Find the probability of rolling
vfiekz [6]
Answer:
Probability of rolling a number greater than 2 = 5/6
Step-by-step explanation:
Given:
Number;
1,2,3,4,5,6,7,8,9,10,11,12
Find:
Probability of rolling a number greater than 2
Computation:
Number greater than 2 = 10
Probability of rolling a number greater than 2 = Number greater than 2 / Total number
Probability of rolling a number greater than 2 = 10 /12
Probability of rolling a number greater than 2 = 5/6
Answer:
The data table is attached below.
Step-by-step explanation:
The average of a set of data is the value that is a representative of the entire data set.
The formula to compute averages is:
Compute the average for drop 1 as follows:
![\bar x_{1}=\frac{1}{3}\times[10+11+9]=10](https://tex.z-dn.net/?f=%5Cbar%20x_%7B1%7D%3D%5Cfrac%7B1%7D%7B3%7D%5Ctimes%5B10%2B11%2B9%5D%3D10)
Compute the average for drop 2 as follows:
![\bar x_{2}=\frac{1}{3}\times[29+31+30]=30](https://tex.z-dn.net/?f=%5Cbar%20x_%7B2%7D%3D%5Cfrac%7B1%7D%7B3%7D%5Ctimes%5B29%2B31%2B30%5D%3D30)
Compute the average for drop 3 as follows:
![\bar x_{3}=\frac{1}{3}\times[59+58+61]=59.33](https://tex.z-dn.net/?f=%5Cbar%20x_%7B3%7D%3D%5Cfrac%7B1%7D%7B3%7D%5Ctimes%5B59%2B58%2B61%5D%3D59.33)
Compute the average for drop 4 as follows:
![\bar x_{4}=\frac{1}{3}\times[102+100+98]=100](https://tex.z-dn.net/?f=%5Cbar%20x_%7B4%7D%3D%5Cfrac%7B1%7D%7B3%7D%5Ctimes%5B102%2B100%2B98%5D%3D100)
Compute the average for drop 5 as follows:
![\bar x_{5}=\frac{1}{3}\times[122+125+127]=124.67](https://tex.z-dn.net/?f=%5Cbar%20x_%7B5%7D%3D%5Cfrac%7B1%7D%7B3%7D%5Ctimes%5B122%2B125%2B127%5D%3D124.67)
The data table is attached below.
Step-by-step explanation:
This is the correct answer.
Even according to calculator and working.
So not quite sure why those options are incorrect?
it will be c
as
negative with negative erased together
