Answer:
3090
Step-by-step explanation:
times 1,030 to 3.
Answer:
I believe your answer is correct. Though I'm not sure if the first picture is right too.
Step-by-step explanation:
Answer:
28-4x
Step-by-step explanation:
Step 1: Open most inner bracket and simplify
=18-2(x+x-5)
=18-2(2x-5)
Step 2: Expand brackets by multiplying 2 in and simplify
=18-2(2x)-2(-5)
=18-4x+10
=28-4x
Therefore the answer is 28-4x
The formula that is useful for solving both of these problems is ...
![(v_2)^2-(v_1)^2=2ad\qquad\text{a=acceleration, d=distance}\\\\ \text{where $v_1$ and $v_2$ are initial and final velocities}](https://tex.z-dn.net/?f=%28v_2%29%5E2-%28v_1%29%5E2%3D2ad%5Cqquad%5Ctext%7Ba%3Dacceleration%2C%20d%3Ddistance%7D%5C%5C%5C%5C%20%5Ctext%7Bwhere%20%24v_1%24%20and%20%24v_2%24%20are%20initial%20and%20final%20velocities%7D)
9. Given v₁=15, a=9.8, d=10, find v₂.
... (v₂)² = 15² + 2·9.8·10
... v₂ = √421 ≈ 20.5 . . . . m/s
10. Given d=12 m when a=-9.8 m/s² and v₂=0, find d when a=0.17·(-9.8 m/s²).
The formula tells us that d=(v₁)²/(2a), which is to say that the distance is inversely proportional to the acceleration. If acceleration is 0.17 times that on earth, distance will be 1/0.17 ≈ 5.88 times that on earth.
(12 m)/0.17 ≈ 70.6 m
Answer:
The answer for this problem is
C) y = -x + 6
Step-by-step explanation:
I know this because I just did the test