Given:
Seven times the smaller of two consecutive even integers is the same as -300 minus 4 times the larger integer.
To find:
The integers
.
Solution:
Let the smaller even integer be x.
So, larger even integer is x+2 because they are consecutive even integers.
Seven times the smaller integer = 7x
-300 minus 4 times the larger integer = -300-4(x+2)
Now,
Divide both sides by 11.
So, the smaller even integer is -28.
So, the larger even integer is -26.
Answer:
57 square inches
Step-by-step explanation:
First consider that a 45 degree sector of a circle is 45/360 of the area of the full circle from which it is cut. This comes out to 1/8 of the full circle area.
The area of a circle of radius 12" is A = π(12 ")^2, or A = 144π.
The area of the sector in question is 1/8 of that, or
A = (1/8)(144π), or A = 18π square inches, or approximately 57 square inches.
Answer:
3.5
Step-by-step explanation:
We are looking for k in the equation
(x+4)(x+k/4) = x^2+7x+k
The left hand side expands to:
x^2+(4+k/4)x+k = x^2+7x+k
Comparing coefficients for the linear terms, we have the equation
(4+k/4)=7
Solving for k:
16+k=28
k=12
Thus the number to be subtracted is 15-k=15-12=3
