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2 years ago

The points (-1.6, 2.7) and (3.2, 7.98) are on the graph of a linear relationship between two variables, r and y.

Mathematics

1 answer:

Aleksandr [31]2 years ago

6 0

Answer:

y = 1.1x +4.46

y = 129.86 for x = 114

Step-by-step explanation:

The two-point form of the the equation for a line is useful for this.

y = (y2 -y1)/(x2 -x1)(x -x1) +y1

y = (7.98 -2.7)/(3.2 -(-1.6))(x -(-1.6)) + 2.7

y = 5.28/4.8(x +1.6) + 2.7

y = 1.1x +1.76 +2.7

y = 1.1x +4.46

When x=114, the value of y is ...

y = 1.1(114) +4.46

y = 129.86

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x = 60

Step-by-step explanation:

The sum of exterior angles in a rectangle is equal to 360

so to find the value of x we need to use all given values and write an equation:

x + 2x + x + 2x = 360 add like terms

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2 years ago

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2 years ago

What is the value of x?

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3 years ago

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1-58. Mr. Wright was making a table to figure out how much it costs to send a certain numt

Drupady [299]

A table of values can be used to represent variables that are directly proportional.

The complete table of proportions is:

$\left[\begin{array}{ccccccccc}Letters&10&2&[150 ]&7&1&500&[420] \\Cost&0.45&0.90&6.75&[0.315]&[0.045 ]&[22.5 ] & 18.90\end{array}\right]$

Given that

$\left[\begin{array}{ccccccccc}Letters&10&2&[\ ]&7&1&500&[\ ] \\Cost&0.45&0.90&6.75&[\ ]&[\ ]&[\ ] & 18.90\end{array}\right]$

Let:

$L \to$ Letters

$C \to$ Cost

Using proportional reasoning, we have:

$C = kL$

Where

$k \to$ ratio of proportion

For the first values of C and L, we have:

$C = kL$

$0.45 = k \times 10$

Divide both sides by 10

$k = 0.045$

So, the equation of proportion is:

$C = 0.045L$

When C = 6.75, we have:

$C = 0.045L$

$6.75 = 0.045L$

Solve for L

$L = \frac{6.75}{0.045}$

$L = 150$

When L = 7, we have:

$C = 0.045L$

$C = 0.045 \times 7$

$C = 0.315$

When L = 1, we have:

$C = 0.045L$

$C = 0.045 \times 1$

$C = 0.045$

When L = 500, we have:

$C =0.045L\\$

$C =0.045 \times 500$

$C =22.5$

When C = 18.90, we have:

$C = 0.045L$

$18.90 = 0.045L$

Solve for L

$L=\frac{18.90}{0.045}$

$L=420$

Hence, the complete table is:

$\left[\begin{array}{ccccccccc}Letters&10&2&[150 ]&7&1&500&[420] \\Cost&0.45&0.90&6.75&[0.315]&[0.045 ]&[22.5 ] & 18.90\end{array}\right]$