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lawyer [7]
3 years ago
8

Both computers and people handle information using which processes?

Computers and Technology
1 answer:
GenaCL600 [577]3 years ago
6 0

Answer:

Explanation:

Both computer and human use the process of encoding, storage and retrieval to process information.

Encoding is the process of putting the information in a format that will be understood by either the human or the computer. The information is then stored in the memory. Both the computer and human have memory where the information will be store. When the information is needed, it is then retrieved from the location in which it was stored.

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Complete the code to finish this program to analyze the inventory for a store that sells purses and backpacks.
sp2606 [1]

Answer:

import csv

fileIn = open("data/bags.txt","r")

countPurse = 0

textFile= csv.reader(fileIn)

for bag in textFile:    

   if bag[ 1 ] == 'purse':

       countPurse = countPurse + int(bag[6])

fileIn.close()

print("Number of purses:",countPurse)

Explanation:

I hope this helps!

3 0
3 years ago
Write a method max() which take a generic singly linked list as an argument and returns the maximum element reference in the lis
max2010maxim [7]

Answer:

See explaination

Explanation:

java code:

class DONALD

{

static class Node

{

int data;

Node next;

}

static Node head=null;

static int largestElement(Node head)

{

Int max=Integer.MIN_VALUE;

while(head!=null)

{

if(max<head.data)

max=head.data;

head=head.next;

}

return max;

}

static int smallestElement(Node head)

{

int min=Integer.MAX_VALUE;

while(head!=null)

{

if(min>head.data)

min=head.data;

head=head.next;

}

return min;

}

static void push(int data)

{

Node newNode=new Node();

newNode.data= data;

newNode.next=(head);

(head)=newNode;

}

static void printList(Node head)

{

while(head!=null)

{

System.out.println(head.data + " -> ");

head=head.next;

}

System.out.println("NULL");

}

public static void main(String[] args)

push(15);

push(14);

push(13);

push(22);

push(17);

System.out.println("Linked list is : ");

printList(head);

System.out.println("Maximum element in linked list: ");

System.out.println(largestelement(head));

System.out.print("Maximum element in Linked List: " );

System.out.print(smallestElement(head));

}

}

6 0
3 years ago
When you use a business class with an object data source, the business class Group of answer choices must have attributes that m
DedPeter [7]

Answer: must have public properties that match the names of the bound fields

Explanation:

When a business class is used with an object data source, the business class must have public properties that match the names of the bound fields.

Having an attribute which match the names of the bound fields isn't necessary as well as having a constructor with parameters that match the names of the bound fields

Therefore, the correct option is B.

3 0
3 years ago
Write a program with a function that accepts a string as an argument and returns the number of uppercase, lowercase, vowel, cons
diamong [38]

Answer:

Explanation:

The following code is written in Python. It is a function called checkString that takes in a string as an argument and loops through each char in that string and checking to see if it is lowercase, uppercase, vowel, consonant, or punctuations. It adds 1 to the correct variable. At the end of the loop it prints out all of the variables. The picture below shows a test output with the string "Brainly, Question."

def checkString(word):

   uppercase = 0

   lowercase = 0

   vowel = 0

   consonants = 0

   punctuation = 0

   vowelArray = ['a', 'e', 'i', 'o','u', 'y' ]

   consonantArray = ['b', 'c', 'd', 'f', 'g', 'h', 'j', 'k', 'l', 'm', 'n', 'p', 'q', 'r', 's', 't', 'v', 'w', 'x', 'y', 'z']

   punctuationArray = ['.', '!', '?', ',', ';', '(', ')']

   for char in word:

       if char.isupper():

           uppercase += 1

       else:

           lowercase += 1

       if char.lower() in vowelArray:

           vowel += 1

       elif char.lower() in consonantArray:

           consonants += 1

       if char in punctuationArray:

           punctuation += 1

   print('Uppercase: ' + str(uppercase))

   print('Lowercase: ' + str(lowercase))

   print('Vowels: ' + str(vowel))

   print('Consonants: ' + str(consonants))

   print('Punctuations: ' + str(punctuation))

8 0
4 years ago
Please give me some names of web pages designed as a hoax or to mislead purposely the reader for some aim.
Tems11 [23]
When ever u download something Add fly pops up so that could be one
6 0
4 years ago
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