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Airida [17]
3 years ago
5

What is 2 5/8 divided by 3/4

Mathematics
1 answer:
gizmo_the_mogwai [7]3 years ago
4 0
2 5/8 divided by 3/4 equals 3 1/2
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|2x-8| + 3 = 5 two solutions
Delicious77 [7]

Answer:

The two solutions are 5 and 3

Step-by-step explanation:

The equation of the absolute has two solutions because IxI = a means x = a and x = -a

Let us solve the question using this fact

∵ I2x - 8I + 3 = 5

→ Subtract 3 from both sides

∴ I2x - 8I + 3 - 5 = 5 - 3

∴ I2x - 8I = 2

By using the fact above

→ 1st solution

∵ 2x - 8 = 2

→ Add 8 to both sides

∴ 2x - 8 + 8 = 2 + 8

∴ 2x = 10

→ Divide both sides by 2 to find x

∴ x = 5

→ 2nd solution

∵ 2x - 8 = -2

→ Add 8 to both sides

∴ 2x - 8 + 8 = -2 + 8

∴ 2x = 6

→ Divide both sides by 2 to find x

∴ x = 3

∴ The two solutions are 5 and 3

6 0
3 years ago
It takes Henry 3 hours to paint someone’s portrait how many hours would it take for him to paint all 8 of his friends’ portraits
Y_Kistochka [10]
If each painting takes 3 hours, and he has to do 8 then he would spend 24 hours doing all 8 portraits
5 0
2 years ago
Read 2 more answers
A sector of a circle makes a 127° angle at its centre. If the arc of the sector has length 36 mm, find
Veseljchak [2.6K]

Answer:

Approximately 68.5\; \rm mm.

Step-by-step explanation:

Convert the angle of this sector to radians:

\begin{aligned}\theta &= 127^{\circ} \\ &= 127^{\circ} \times \frac{2\pi}{360^{\circ}} \\ &\approx 2.22\end{aligned}.

The formula s = r\, \theta relates the arc length s of a sector of angle \theta (in radians) to the radius r of this sector.

In this question, it is given that the arc length of this sector is s = 36\; \rm mm. It was found that \theta = 2.22 radians. Rearrange the equation s = r\, \theta to find the radius r of this sector:

\begin{aligned} r&= \frac{s}{\theta} \\ &\approx \frac{36\; \rm mm}{2.22} \\ &\approx 16.2\; \rm mm\end{aligned}.

The perimeter of this sector would be:

\begin{aligned}& 2\, r + s \\ =\; & 2 \times 16.2\; {\rm mm} + 36\; {\rm mm} \\ =\; & 68.5\; \rm mm\end{aligned}.

8 0
2 years ago
The formula F=9/5(K−273.15)+32
Lyrx [107]
Just subtract 32, then divide by 9/5 (or multiply by the reciprical) then add 273.15.
K=5/9(F-32)+273.15
3 0
3 years ago
Maclaurin series of sinx
olga nikolaevna [1]

Answer:

cos(u) and sin(u) can be expanded in with a Maclaurin series, and cos(c) and sin(c) are constants.

Step-by-step explanation:

thats it

7 0
3 years ago
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