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2 years ago

15

Consider this function:

1 answer:

Digiron [165]2 years ago

3 0

Answer:

this is why im failing math

Step-by-step explanation:

yes

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FIRST ANSWER GETS BRAINLIEST

Talja [164]

The answer is

121.5

4 0

2 years ago

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Given A = {1, 3, 5}, B = {2, 4, 6} and C={1, 2, 3, 4, 5, 6}, then A ∪ (B ∩ C)

Serggg [28]

B ∩ C is an intersection, which means only values that are present in both B and C are picked. So...
B ∩ C = {2, 4, 6}
A ∪ (B ∩ C) is a union, which means you combine all values, but discard duplicates. So...
A ∪ (B ∩ C) = {1, 2, 3, 4, 5, 6}

8 0

3 years ago

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Square root of 0.25 in fraction form

Nady [450]

First off, let's convert 0.25 to a fraction, notice, it has two decimals, therefore, we'll use two zeros on the denominator, two decimals, two zeros, thus,

$\bf 0.\underline{25}\implies \cfrac{025}{1\underline{00}}\implies \cfrac{25}{100}\\\\
-------------------------------\\\\
\sqrt{0.25}\implies \sqrt{\cfrac{25}{100}}\implies \sqrt{\cfrac{5^2}{10^2}}\implies \cfrac{5}{10}\implies \cfrac{1}{2}$

5 0

3 years ago

Help please i’m in the middle of a test

MA_775_DIABLO [31]

Answer:

None of your options

Step-by-step explanation:

$(7 - 3i) + ( x - 2i)^2 -(4i^2 + x^2)\\\\(7 - 3i) + (x^2 - 4 - 4xi) - (-4 + x^2)\\\\7 - 3i + x^2 - 4 - 4xi + 4 - x^2\\\\7 -i(3+4x) - 4 + 4 - x^2 + x^2\\\\7 - (4x + 3)i$

6 0

3 years ago

In the system shown below, what are the coordinates of the solution that lies in quadrant IV?

katrin2010 [14]

Answer:

The coordinates of the solution that lies in quadrant IV are (2, -5)

Step-by-step explanation:

We have 2 equations, the first of an ellipse and the second of a circumference.

$2x^2+y^2=33\\x^2+y^2+2y=19$

To solve the system solve the second equation for x and then substitute in the first equation

$x^2+y^2+2y=19\\\\x^2 = 19 -y^2 -2y$

So Substituting in the first equation we have

$x^2 = 19 -y^2 -2y\\\\2(19 -y^2 -2y)+y^2=33\\\\38 -2y^2-4y +y^2 = 33\\\\-y^2-4y+5=0\\\\y^2 +4y-5 = 0$

Now we must factor the quadratic expression.

We look for two numbers that multiply as a result -5 and add them as result 4.

These numbers are -1 and 5.

Then the factors are

$y^2 +4y-5 = 0\\\\(y-1)(y+5) = 0$

Therefore the system solutions are:

$y = 1$ ; $y = -5$

In the 4th quadrant the values of x are positive and the values of y are negative.

So we take the negative value of y and substitute it into the system equation to find x

$y=-5\\\\2x^2+(-5)^2=33\\\\2x^2 = 33-25\\\\2x^2 = 8\\\\x^2 = 4$

$x = 2$ , and $x= -2$

In the 4th quadrant the values of x are positive

So we take the positive value of x

<em><u>the coordinates of the solution that lies in quadrant IV are (2, -5)</u></em>

6 0

3 years ago

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