Answer:
3
Step-by-step explanation:
see image below:)
Consider the quadratic function f(y) = 8y2 – 7y + 6. What is the constant of the function?
1 answer:
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Answer:
- Constraints: x + y ≤ 250; 250x +400y ≤ 70000; x ≥ 0; y ≥ 0
- Objective formula: p = 45x +50y
- 200 YuuMi and 50 ZBox should be stocked
- maximum profit is $11,500
Step-by-step explanation:
Let x and y represent the numbers of YuuMi and ZBox consoles, respectively. The inventory cost must be at most 70,000, so that constraint is ...
250x +400y ≤ 70000
The number sold will be at most 250 units, so that constraint is ...
x + y ≤ 250
Additionally, we require x ≥ 0 and y ≥ 0.
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A profit of 295-250 = 45 is made on each YuuMi, and a profit of 450-400 = 50 is made on each ZBox. So, if we want to maximize profit, our objective function is ...
profit = 45x +50y
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A graph is shown in the attachment. The vertex of the feasible region that maximizes profit is (x, y) = (200, 50).
200 YuuMi and 50 ZBox consoles should be stocked to maximize profit. The maximum monthly profit is $11,500.
Answer:
As we get closer to x=-3, the limit is approaches -1, on both sides of -3 so this is a good limit so c is 8.
Step-by-step explanation:
In order for a limit to exists, the left side limit must exist and right side limit must exist and on top of that, they must be equal to each other.
In this case, this a piece wise function and by definition of a limit that exist, the limit of this piece wise function as x approaches 3 from either side, must be equal.
We let x=-3 for the top equation.
So we set the second equation equal to -1.
So the value of c is 8. We can prove this by graphing as well.
