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3 years ago

Wouldn't this be true ?

Mathematics

2 answers:

Nookie1986 [14]3 years ago

7 0

Yes It would Definitely be true :)

Lana71 [14]3 years ago

4 0

I think this is true

You might be interested in

What is 143/15 simplified

V125BC [204]

$\sf \frac{143}{15}=?$

$\sf{ 15 \times 9 = 135}$

$\sf{143- 135 = 8}$

$\sf{ \frac{143}{15} = \frac{135+8}{15} = \frac{135}{135} + \frac{8}{15}$

$\sf{ \frac{143}{15} =\boxed{\huge{ 9 \frac{8}{15} }}}$

8 0

3 years ago

Read 2 more answers

A 500500-gallon tank initially contains 200200 gallons of brine containing 100100 pounds of dissolved salt. brine containing 11

mixer [17]

Let $A(t)$ denote the amount of salt in the tank at time $t$ . We're given that the tank initially holds $A(0)=100$ lbs of salt.

The rate at which salt flows in and out of the tank is given by the relation

$\dfrac{\mathrm dA}{\mathrm dt}=\underbrace{\dfrac{11\text{ lb}}{1\text{ gal}}\times\dfrac{44\text{ gal}}{1\text{ min}}}_{\text{rate in}}-\underbrace{\dfrac{A(t)}{200+(44-11)t}\times\dfrac{11\text{ gal}}{1\text{ min}}}_{\text{rate out}}$
$\implies A'(t)+\dfrac{11}{200+33t}A(t)=484$

Find the integrating factor:

$\mu(t)=\exp\left(\displaystyle\int\frac{11}{200+33t}\,\mathrm dt\right)=(200+33t)^{1/3}$

Distribute $\mu(t)$ along both sides of the ODE:

$(200+33t)^{1/3}A'(t)+11(200+33t)^{-2/3}A(t)=484(200+33t)^{-1/3}$
$\bigg((200+33t)^{1/3}A(t)\bigg)'=484(200+33t)^{-1/3}$
$A(t)=484\displaystyle\int(200+33t)^{-1/3}\,\mathrm dt$
$A(t)=22(200+33t)^{2/3}+C$

Since $A(0)=100$ , we get

$100=22(200)^{2/3}+C\implies C\approx-652.39$

so that the particular solution for $A(t)$ is

$A(t)=22(200+33t)^{2/3}-652.39$

The tank becomes full when the volume of solution in the tank at time $t$ is the same as the total volume of the tank:

$200+(44-11)t=500\implies 33t=300\implies t\approx9.09$

at which point the amount of salt in the solution would be

$A(9.09)\approx733.47\text{ lb}$

4 0

3 years ago

Help pls <br> 8 + 6x = -4

gavmur [86]

Answer:

x=-2

Step-by-step explanation:

5 0

4 years ago

Read 2 more answers

An unknown number is not equal to 3.6 but rounds to 3.6 when rounded to the nearest tenth, what could be the number?

dedylja [7]

Answer:

3.55-3.59

Step-by-step explanation:

to round off to the nearest whole number, look at the first number after the decimal, if it is less than 5, add zero to the units term, If it is equal or greater than 5, add 1 to the units term.

So numbers that would be rounded off to 3.6 have to have an hundredth value equal or greater than 5

they include

3.55

3.56

3.57

3.58

3.59

3 0

3 years ago

Given a non-linear system: y=x^3 - 3x^2 - 1 a) Find the linear approximation of the system at the point (1, -3) b) Plot the syst

Zepler [3.9K]

$\mbox{First, we compute the derivative of $y$ at $x_0=1$. So, we get}\\$$ y' = 3x^2 - 6x \, , \, y'(1) = -3 $$$ .