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Anna35 [415]
3 years ago
12

184 sixth graders are going on a field trip. There needs to be one chaperone for every four students. If a bus can hold 50 peopl

e, how many busses will they need for the trip? Hint: You can't use part of a bus! *
Mathematics
1 answer:
Kisachek [45]3 years ago
7 0

Answer:

5 buses

Step-by-step explanation:

Total number of 6th graders going for the field trip = 184

Step 1

Divide the total number of students by 4

184/4 = 46

We have 46 groups of six graders.

Step 2

There needs to be one chaperone for every four students.

We have 46 groups of six graders

This means there is need for 1 chaperone per group

Hence, we have 46 chaperones

Step 3

Find total number of people going for the field trip

184 students + 46 chaperones

= 230 people

Step 4

If a bus can hold 50 people, how many buses will they need for the trip?

50 people = 1 bus

230 people = ??y

50 × y = 230

y = 230/50

y = 4.6 buses

Hence, 4.6 buses would be needed but since we can't have 0.6(part) of a bus figuratively, as buses come in whole numbers, we approximate to the nearest whole number

= 4.6 ≈ 5

Therefore, they would be needing 5 buses for the trip.

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xz_007 [3.2K]

Answer:

The probability that X is between 1.48 and 15.56 is P(1.48 \leq X \leq 15.56) = 0.919

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

X is a normally distributed random variable with a mean of 8 and a standard deviation of 4.

This means that \mu = 8, \sigma = 4

The probability that X is between 1.48 and 15.56

This is the pvalue of Z when X = 15.56 subtracted by the pvalue of Z when X = 1.48. So

X = 15.56

Z = \frac{X - \mu}{\sigma}

Z = \frac{15.56 - 8}{4}

Z = 1.89

Z = 1.89 has a pvalue of 0.9706

X = 1.48

Z = \frac{X - \mu}{\sigma}

Z = \frac{1.48 - 8}{4}

Z = -1.63

Z = -1.63 has a pvalue of 0.0516

0.9706 - 0.0516 = 0.919

Write out the probability notation for this question.

P(1.48 \leq X \leq 15.56) = 0.919

The probability that X is between 1.48 and 15.56 is P(1.48 \leq X \leq 15.56) = 0.919

5 0
3 years ago
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