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3 years ago

Medea found the missing measure using a proportion of the reduced trapezoid.

Mathematics

2 answers:

Fofino [41]3 years ago

6 0

Answer:

Step-by-step explanation:

A) In step 1, the corresponding parts are in different positions.

Elena-2011 [213]3 years ago

5 0

Answer: The answer is Step 1

Step-by-step explanation:

i just did the assignment :)

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What plus what equals -8 ?

Vinil7 [7]

Answer:

-4+-4

Step-by-step explanation:

3 0

2 years ago

A kangaroo hopped \dfrac13 3 1 ? of the distance to the lake with her baby in her pouch. She hopped the remaining 70407040 yards

kogti [31]

Answer:

6 miles.

Step-by-step explanation:

Let x be the total distance hoped by Kangaroo to the lake.

We have been given that a kangaroo hopped 1/3 of the distance to the lake with her baby in her pouch.

She hopped the remaining 7040 yards without her baby in her pouch. This means that 2/3 of total distance (x) is 7040. We can represent this information in an equation as:

$\frac{2}{3}*x=7040$

Let us solve for x by multiplying both sides of our equation by 3/2.

$\frac{3}{2}*\frac{2}{3}*x=\frac{3}{2}*7040$

$x=3*3520$

$x=10560$

Therefore, the total distance hoped by the kangaroo is 10560 yards.

1 mile = 1760 yards

Let us convert this distance in miles by dividing 10560 yards by 1760.

$\text{The kangaroo hoped}=\frac{10560\text{ yards}}{\frac{1760\text{ yards}}{\text{Mile}}}$

$\text{The kangaroo hoped}=\frac{10560\text{ yards}}{1760}\times \frac{\text{ Mile}}{\text{ yards}}$

$\text{The kangaroo hoped}=\frac{10560}{1760}\times\text{ Mile}$

$\text{The kangaroo hoped}=6\text{ Miles}$

Therefore, the kangaroo hoped 6 miles to the lake.

3 0

3 years ago

Express answer in exact form.

Ratling [72]

Area of circle = πr²
= 64π
The cord will subtend a semicircle of diameter 8", radius 4". The area of this semicircle:
1/2 πr²
= 0.5 x 4² x π
= 8π
Area of larger region = area of circle - area of semicircle
= 64π - 8π
= 56π inch²

5 0

3 years ago

Read 2 more answers

The right arrow symbol used to show the transition from a point to its image after a transformation is not contained within the

Bumek [7]

Given:

Vertices of triangle ABC are A (1,4), B(3,−2) and C(4,2).

Triangle ABC reflected over the x-axis to get the triangle A'B'C'.

To find:

The coordinates of the image A'B'C'.

Solution:

If a figure reflected over the x-axis, then rule of transformation is

$(x,y)\to (x,-y)$

Now, using this rule, we get

$A(1,4)\to A'(1,-4)$

$B(3,-2)\to B'(3,2)$

$C(4,2)\to C'(4,-2)$

Therefore, the coordinates of the image A'B'C' after a reflection over the x-axis are A'(1,-4), B'(3,2) and C'(4,-2).

7 0

3 years ago

Zahid is paid a set wage of $774.72 for a 36-hour week, plus time-and-a-half for overtime. In one particular week he worked 43 h

Llana [10]

Answer:

$1000.68

Step-by-step explanation:

$\frac{774.72}{36} = 21.52 \: (per \: hour) \\ \frac{21.52}{2} = 10.76 \: \\ 21.52 + 10.76 = 32.28(per \: hour \: of \: over \: time) \\ \\ 43 - 36 = 7(hours \: of \: overtime) \\ \\ 7 \times 32.28 = 225.96 \\ 774.72 + 225.96 = 1000.68$

8 0

2 years ago