If you earned 892.50 after depositing 1400 at 4.25% simple interest, how long was it invested ? Using the simple interest formul
a, solve for t. Formula I=Prt
1 answer:
Answer:
Time t = 15 years
Step-by-step explanation:
Interest = 892.50
Principal = 1400
Rate = 4.25%
Time = unknown
But
interest I = Principal p * rate r * time t
Time t = interest I/(principal P * rate r)
Time t=( 892.50*100)/(1400*4.25)
Time t=89250/5950
Time t = 15 years
You might be interested in
Format: y = mx + b
m = slope, b = y intercept
Solution: slope: -2, y intercept: 0
Answer:
x = 122
Step-by-step explanation:
x = 122 because of alternate interior angles
<h2>218 = 49 + 169 = 7² + 13² </h2><h2><u>218 = 7² + 13²</u> </h2><h2> </h2><h2> </h2><h2> </h2><h2 />
APR is different than other compounding periods because you would need to find some equivelancy to compare things at.
Answer:
Rate of change = (1350 - 750)/(2010 - 2000) = 600/10 = $60
Initial value = $750
Equation is y = 60x + 750; where y is the amount charged to customer and x is the number of years from 2000.