For the first 60 positive integers, a = 1, n = 60, l = 60.
Sn = n/2(a + l)
s = 60/2(1 + 60) = 30(61)
For the next 60 positive integer, a = 61, n = 60, l = 120
Sum = 60/2(61 + 120) = 30(61 + 120) = 30(61) + 30(120) = s + 3600
Sum of first 120 positive integers = s + s + 3600 = 2s + 3600
Answer:
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Answer:
Factor by which kinetic energy increase = 4 times
Step-by-step explanation:
Given,
- Mass of the car, v1 = 1500 kg
- initial speed of car = 35 miles/h

= 15.64 m/s
Initial kinetic energy of the car is given by,


= 183606.46 J
- Final velocity of car v2 = 70 miles/hour

= 31.29 m/s
So, final kinetic energy of car is given by


= 734425.84 J
Now, the ratio of final to initial kinetic energy can be given by,

Hence, the kinetic energy will increase by 4 times.