Answer: See attached table
Step-by-step explanation:
![\begin{table}[]\begin{tabular}{lllll} & & & & \\ & & & & \\ & & & & \\ & & & & \end{tabular}\end{table}](https://tex.z-dn.net/?f=%5Cbegin%7Btable%7D%5B%5D%5Cbegin%7Btabular%7D%7Blllll%7D%20%26%20%20%26%20%20%26%20%20%26%20%20%5C%5C%20%26%20%20%26%20%20%26%20%20%26%20%20%5C%5C%20%26%20%20%26%20%20%26%20%20%26%20%20%5C%5C%20%26%20%20%26%20%20%26%20%20%26%20%5Cend%7Btabular%7D%5Cend%7Btable%7D)
+---+---+---+
| 1 | 8 | 2 |
+---+---+---+
| 6 | 4 | 2 |
+---+---+---+
| 5 | 0 | 7 |
+---+---+---+
<u>Proofs:</u>
First row: 1+6+5 = 12
Second row: 8+4+0 = 12
Third row: 2+2+7 = 12
First column: 1+8+2 = 12
Second column: 6+4+2 = 12
Third column: 5+0+7 = 12
Diagonal starting from top left to bottom right: 1+4+7 = 12
Diagonal staring from top right to bottom left: 2+4+5 = 12
5 less (-5) than 1/3 of number (n/3) is (=) 2 more than (2+) half of the number (n/2)
-5+n/3=2+n/2
add 5 to both sides
n/3=n/2+7
times 6 both sides
2n=3n+42
minus 2n both sides
0=n+42
minus 42 boh sides
-42=n
the number is -42
the number is 18
Answer:
a
Step-by-step explanation:
Sin = - 4/8
Quadrant IV = only cosine is positive
a = height (4)
b = base ( 8^2-4^2=b^2
b = 6.93 @
c = hypothenuse(8)
cos =
/8
tan = - 4/
sec = 1/cos
1/cos = 1/ (
/8)
sec = 8/
csc = 1/sin
1/sin = 1/(-4/8)
csc = - 2
cot = 1/tan
1/tan = 1/(-4/
)
cot = -
/4
