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3 years ago

Please Helpppppppp with this question

Mathematics

1 answer:

Slav-nsk [51]3 years ago

6 0

Answer: pls. mark as Brainlyist I needz Points PLZ!

Step-by-step explanation:

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Directions:Use the product rule to simplify the following monomials.

attashe74 [19]

13) Answer: $-3a^3b^2$

$\left(-6a^2b\right)\left(\frac{1}{2}ab\right)$

$=-6a^2b\frac{1}{2}ab$

$=-6a^2b^2\frac{1}{2}a$

$=-6a^3b^2\frac{1}{2}$

$=-3a^3b^2$

14) Answer: $8y^5x$

$12y\left(\frac{2}{3}xy^4\right)$

$=12\cdot \frac{2}{3}xy^{1+4}$

$=12\cdot \frac{2}{3}xy^5$

$=\frac{2\cdot \:12xy^5}{3}$

$=\frac{24y^5x}{3}$

$=8y^5x$

6 0

3 years ago

Jordan places two boards end to end to make one shelf. The first board is 47/100 meter long, the second board is 5/10 meter long

MrRissso [65]

97/100 bdbdbd the

bdbd

5 0

3 years ago

Read 2 more answers

If $800 is deposited in an account paying 7% annual interest, compounded continuously, how long will it take for the account to

Leona [35]

<u>Answer: </u>

$800 will become $ 1300 in 6.94 years when compounded continuously at the annual interest rate of 7%.

<u>Solution: </u>

Given that

Amount deposited = $800,

Rate if interest = 7% = 0.07

Required amount = $1300

And most important thing that interest is compounded continuously.

Formula of Amount where interest is compounded continuously is as follows

$A=P e^{\mathrm{rt}}$

Where A is final amount,

P is principal Amount,

r = rate of interest

t = duration in years

In our case A = $1300, P = $800, r = 0.07. We need to evaluate “t” that is number of year.

On substituting given values in formula of amount we get

$1300=800 e^{0.07 t}$

$\frac{1300}{800} = \mathrm{e}^{0.07 \mathrm{t}}$

$1.625=\mathrm{e}^{0.07 \mathrm{t}}$

Taking ln both the sides

$\ln (1.625)=(0.07 \mathrm{t}) \ln ^{e}$

$l n^{e}$ = 1 .So we get,

ln(1.625) = 0.07t

$t = \frac{ln 1.625}{0.07}$

= 6.9358 ≈ 6.94 years

Hence $800 will become $ 1300 in 6.94 years when compounded continuously at the annual interest rate of 7%.

8 0

3 years ago

A survey of athletes at a high school is conducted, and the following facts are discovered: 57% of the athletes are football pla

LekaFEV [45]

Answer:

The probability that the athlete is either a football player or a basketball player = $\frac{66}{100}$ = 0.66

Step-by-step explanation:

Football players = 57 %

Basketball players = 17 %

Both game players = 8 %

Players who plays either one game = ( Football players ) + ( Basketball players) - ( Both game players )

⇒ 57 + 17 - 8 = 66 %

Now, the probability that the athlete is either a football player or a basketball player = $\frac{66}{100}$ = 0.66

8 0

3 years ago

Annabeth has $29.00 to spend at the sporting goods store.

alexandr1967 [171]

Hi there!

»»————-　★　————-««

I believe your answer is:

The soccer ball.

»»————-　★　————-««

Here’s why:

⸻⸻⸻⸻

$\boxed{\text{Solving for 'c'...}}\\\\15.32 + c = 29.00\\-----------\\\rightarrow 15.32 - 15.32 = 29.00 - 15.32\\\\\rightarrow \boxed{13.68}$

⸻⸻⸻⸻

She would have $13.68 dollars left. Her second item should be the soccer ball.

»»————-　★　————-««

Hope this helps you. I apologize if it’s incorrect.

3 0

3 years ago