I'm pretty sure it's team jaguars
Answer:
Step-by-step explanation:
![\dfrac 12 \left[\sin(a+b)+\sin(a-b) \right]\\\\\\=\dfrac 12\left[ 2 \sin a \cos b\right]\\\\\\=\sin a \cos b](https://tex.z-dn.net/?f=%5Cdfrac%2012%20%5Cleft%5B%5Csin%28a%2Bb%29%2B%5Csin%28a-b%29%20%5Cright%5D%5C%5C%5C%5C%5C%5C%3D%5Cdfrac%2012%5Cleft%5B%202%20%5Csin%20a%20%5Ccos%20b%5Cright%5D%5C%5C%5C%5C%5C%5C%3D%5Csin%20a%20%5Ccos%20b)
Step-by-step explanation:
I'll do line A for you and you can use the formulas to solve lines B and C yourself, since its good for you to practice doing these questions yourself
a)
The gradient, m, is calculated using m = (y2-y1)/(x2-x1) where x1,x2,y1 and y2 can be any ordered pairs on the line. I'm going to use (4,0) and (7,3) as the 2 points.
m = (3-0)/(7-4) = 3/3 = 1
b)
The y-intercept is where the line intersects with the x-axis. In this case (0,-4)
c)
The equation of a linear line is y=mx+b (or c depending on which country you are from)
y = 1x-4
y=x-4
Now try the other 2 lines yourself!
If this answer has helped you, considered making this the brainliest answer!
Answer:
f•g(x) = f(x)•g(x)
f•g(x) = (2x-1) (x²-2x+1)
= 2x³-4x²+2x-x²+2x-1
= 2x³-5x²+4x-1
When they are collinear, they lie on the same straight line
