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Vlad1618 [11]
3 years ago
6

The distance traveled can be calculated using the formula D

Mathematics
1 answer:
Dmitry [639]3 years ago
3 0
Maybe b 60 km/hr for 2 hours
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. Office productivity is relatively low when the employees feel no stress about their work or job security. However, high levels
Ray Of Light [21]

Answer:

Step-by-step explanation:

The plot chart below best represents the relationship between stress and productivity in the workplace. As seen in the chart both high and low levels of stress equate to very low productivity levels for employees in the workplace. While just enough stress creates very productive employees. This tends to be because employees are worried about the possibility of losing their jobs so they work hard in order to keep the job but are not so worried that they think it will happen tomorrow and become burned out.

3 0
3 years ago
30 POINTS FOR SOMEONE WHO ANSWERS MY QUESTIONS PLS IM FAILING
ziro4ka [17]

Answer:

ok i will answer only two which two do you want me to answer

Step-by-step explanation:

7 0
2 years ago
Nick bought a new car.
ira [324]

Using an exponential function, it is found that it takes 5.42 years for the car to halve in value.

<h3>What is an exponential function?</h3>

A decaying exponential function is modeled by:

A(t) = A(0)(1 - r)^t

In which:

  • A(0) is the initial value.
  • r is the decay rate, as a decimal.

In this problem, the car depreciates 12% a year in value, hence r = 0.12 and the equation is given by:

A(t) = A(0)(0.88)^t.

It halves in value at t years, for which A(t) = 0.5A(0), hence:

A(t) = A(0)(0.88)^t

0.5A(0) = A(0)(0.88)^t

(0.88)^t = 0.5

\log{(0.88)^t} = \log{0.5}

t\log{0.88} = \log{0.5}

t = \frac{\log{0.5}}{\log{0.88}}

t = 5.42.

It takes 5.42 years for the car to halve in value.

More can be learned about exponential functions at brainly.com/question/25537936

#SPJ1

9 0
2 years ago
Expand the expression: 5(d +7)<br> show work pls so i can understand
Tresset [83]
5(d + 7)
multiply 5 to d, then to 7
5d + 35
3 0
3 years ago
A store finds that its sales revenue changes at a rate given by S'(t) = −30t2 + 420t dollars per day where t is the number of da
allochka39001 [22]

Answer:

Step-by-step explanation:

Give the rate of change of sales revenue of a store modeled by the equation S'(t)= -30t^{2} + 420t. The Total sales revenue function S(t) can be gotten by integrating the function given as shown;

\int\limits {S'(t)} \, dt = \int\limits ({-30t^{2}+420t }) \, dt \\S(t) = \frac{-30t^{3} }{3}+\frac{420t^{2} }{2}\\  S(t)= -10t^{3} +210t^{2} \\

a) The total sales for the first week after the campaign ends (t = 0 to t = 7) is expressed as shown;

Given\ S(t) = -10t^{3} + 210t^{2}

S(0) = -10(0)^{3} + 210(0)^{2}\\S(0) = 0\\S(7) = -10(7)^{3} + 210(7)^{2}\\S(7) = -3430+10,290\\S(7) = 6,860

Total sales = S(7) - S(0)

= 6,860 - 0

Total sales for the first week = $6,860

b) The total sales for the secondweek after the campaign ends (t = 7 to t = 14) is expressed as shown;

Total sales for the second week = S(14)-S(7)

Given S(7) = 6,860

To get S(14);

S(14) = -10(14)^{3} + 210(14)^{2}\\S(14) = -27,440+41,160\\S(14) = 13,720

The total sales for the second week after campaign ends = 13,720 - 6,860

= $6,860

8 0
3 years ago
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