We want to find
, for
.
Recall the product rule: for 2 differentiable functions f and g, the derivative of their product is as follows:
.
Thus,
![y'=[(x^2+2)^3]'[(x^3+3)^2]+[(x^3+3)^2]'[(x^2+2)^3]\\\\ =3(x^2+2)^2(x^3+3)^2+2(x^3+3)(x^2+2)^3](https://tex.z-dn.net/?f=y%27%3D%5B%28x%5E2%2B2%29%5E3%5D%27%5B%28x%5E3%2B3%29%5E2%5D%2B%5B%28x%5E3%2B3%29%5E2%5D%27%5B%28x%5E2%2B2%29%5E3%5D%5C%5C%5C%5C%20%3D3%28x%5E2%2B2%29%5E2%28x%5E3%2B3%29%5E2%2B2%28x%5E3%2B3%29%28x%5E2%2B2%29%5E3)
Answer: A)
.
Answer:
t1 = $25m
t2 = $(10m + 100)
Step-by-step explanation:
Here we want to write equations
Kiera chose plan 1
$25 monthly and no joining fee
So the amount after m months will be 25 * m
t1 = $25m
Trina chose plan 2
$10 a month and $100 joining fee
after m months , total payment will be
10(m) + 100 = $(10m + 100)
Thus t1 = $25m and t2 = $(10m + 100)
Answer:
My brain just exploded. I tried imagining what the shape would look like, and that didn't work. Also, I tried drawing the shape and that didn't work. I have no idea what the shape looks like. If you still need help with this question, maybe you can repost it with an image attached so we can know what the shape looks like.
Answer:
The answer is below
Step-by-step explanation:
From the graph, we can see that both segment 1 and segment 2 are positive slopes (as the time increases, the number of people increases)
Segment 1 is more steep than segment 2 (the number of people increases in segment 1 more than segment 2). This means that the number of people entering the arena in segment 1 was higher than the rate of people entering the arena in segment 2.
The range is the difference between the LOWEST value and the HIGHEST value.
The range is the set of POSSIBLE output values, and that is shown on the Y-AXIS!!
