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kap26 [50]
3 years ago
10

If 18 g of a radioactive substance are present initially and 9 yr later only 9 g remain, how much of the substance will be prese

nt after 12 yr?
After 12 yr there will be g of a radioactive substance.
(Round the final answer to three decimal places as needed. Round all intermediate values to seven decimal places as needed.)
Mathematics
1 answer:
kvasek [131]3 years ago
8 0

Answer:

Him hhhuuu vividly

Step-by-step explanation:

You might be interested in
3) Write the inequality that
masha68 [24]

Answer:

  • See below

Step-by-step explanation:

Owing represent a negative balance.

<u>So the inequality for this case is:</u>

  • - 26.00 > - 147.00
3 0
3 years ago
when you reverse the digits in a certain two digit number you increase its value by 9 find the sum of its digits is 17
melamori03 [73]
The answer is 80.
80 flipped is 08, which is equal to 8, then 8+9=17
3 0
3 years ago
Drag the tiles to the correct boxes to complete the palrs.
Brut [27]

Answer:

(f+g)(2)  = 4

(f-g)(4) = 8

(f ÷g)(2) = 7

(f x g)(1) = 0

Step-by-step explanation:

We are given these following functions:

f(x) = 2x + 3

g(x) = x - 1

(f+g)(2)

(f+g)(x) = f(x) + g(x) = 2x + 3 + x - 1 = 3x - 2

At x = 2

(f+g)(2) = 3(2) - 2 = 6 - 2 = 4

Then

(f+g)(2)  = 4

(f-g)(4)

(f-g)(x) = f(x) - g(x) = 2x + 3 - (x - 1) = 2x + 3 - x + 1 = x + 4

At x = 4

(f-g)(4) = 4 + 4 = 8

Then

(f-g)(4) = 8

(f ÷g)(2)

(f \div g)(x) = \frac{f(x)}{g(x)} = \frac{2x+3}{x-1}

At x = 2

(f \div g)(2) = \frac{7}{1} = 7

Then

(f ÷g)(2) = 7

(f x g)(1)

(f \times g)(x) = f(x)g(x) = (2x+3)(x-1) = 2x^2 -2x + 3x - 3 = 2x^2 + x - 3

Then

(f \times g)(1) = 2(1)^2 + 1 - 3 = 3 + 1 - 3 = 0

So

(f x g)(1) = 0

4 0
3 years ago
What is the value of x?<br> 6.75+ x = 131
yanalaym [24]

Answer:

x = 497/4 = 124.250

Step-by-step explanation:

Step  1  :

           27

Simplify   ——

           4

Equation at the end of step  1  :

  27          

 (—— +  x) -  131  = 0

  4          

Step  2  :

Rewriting the whole as an Equivalent Fraction :

2.1   Adding a whole to a fraction

Rewrite the whole as a fraction using  4  as the denominator :

        x     x • 4

   x =  —  =  —————

        1       4  

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

2.2       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

27 + x • 4     4x + 27

——————————  =  ———————

    4             4  

Equation at the end of step  2  :

 (4x + 27)    

 ————————— -  131  = 0

     4        

Step  3  :

Rewriting the whole as an Equivalent Fraction :

3.1   Subtracting a whole from a fraction

Rewrite the whole as a fraction using  4  as the denominator :

          131     131 • 4

   131 =  ———  =  ———————

           1         4  

Adding fractions that have a common denominator :

3.2       Adding up the two equivalent fractions

(4x+27) - (131 • 4)     4x - 497

———————————————————  =  ————————

         4                 4    

Equation at the end of step  3  :

 4x - 497

 ————————  = 0

    4    

Step  4  :

When a fraction equals zero :

4.1    When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, multiplys both sides of the equation by the denominator

Here's how:

 4x-497

 —————— • 4 = 0 • 4

   4  

Now, on the left hand side, the  4  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  4x-497  = 0

Solving a Single Variable Equation :

4.2      Solve  :    4x-497 = 0

Add  497  to both sides of the equation :

                     4x = 497

Divide both sides of the equation by 4:

                    x = 497/4 = 124.250

One solution was found :

                  x = 497/4 = 124.250

Processing ends successfully

plz mark me as brainliest :)

6 0
3 years ago
Find HCF OF 78,175,195​
Veseljchak [2.6K]

Answer:

not possible as you cannot factories any more

7 0
3 years ago
Read 2 more answers
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