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tatuchka [14]
4 years ago
11

5 less than one fourth of x is y

Mathematics
1 answer:
dimulka [17.4K]4 years ago
6 0

y = 1/4x - 5

Hope this helps!

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Twice the sum of k and 4
kodGreya [7K]
The answer is 2(k+4)
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What is 2 thirds divided by one half? 
erastovalidia [21]
Its 2/3 divided in half. 
It's 1/3 Im pretty sure 

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3 years ago
A man buys a goat for $60 than he sells it for $70 he buys the same goat for $80 than sells it for $90 how much money does the m
castortr0y [4]

Answer: The man has 10$.

Step-by-step explanation:

We start with the number 60. He sells the goat for 70 dollars, and makes a 10 dollar profit. Then, he buys it for 80$, leaving him with 0. But then he sells it for 90$, making another profit of 10$.

7 0
4 years ago
The greatest common factor (GCF) of x^3, x^7, x^9 is ?<br> Please help
solong [7]

Answer:

x^3

Step-by-step explanation:

Let the greatest common factor of a,b,c such that a,b,c \in\mathbb{Z} and they are not all equal to zero, d is the common divisor of a and b. Therefore, d \mid a and d \mid b

You can write

D(a) = \{d \in\mathbb{Z} : d \mid a\}

D(b) = \{d \in\mathbb{Z} : d \mid b\}

The greatest common factor of a,b is given as

D(a,b) = \{d \in\mathbb{Z} : d \mid a \text{ and } d \mid b\}

and

D(a, b) = D(a) \cap D(b)

This happens because D(a,b) is upper bounded because if a\neq 0 then d \leq |a|

for all d\in D(a, b). Therefore, the set D(a, b) has the greatest elements.

Taking x^3, x^7, x^9 such that x>0

You can note that x^7 = x^3 \cdot x^4 and x^9 = x^3 \cdot x^6 =  x^3 \cdot x^3 \cdot x^3

Therefore, the greatest common factor is x^3

Note: x^3 \cap x^7 \cap x^9 = x^3

6 0
3 years ago
There Are 200 Employees In your company. Fifty of them do not have company health insurance . What Percentage Of the employees d
Anettt [7]
25 percent of the employees does not have company Health Insurance
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4 years ago
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