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Anika [276]
3 years ago
6

F(x) = 4x^3+...+ 9list all possible rational zeroes of the function​

Mathematics
1 answer:
Maru [420]3 years ago
7 0

The Rational Root Theorem says any rational zeros of f must be a fraction with a factor of the constant (9 here) in the numerator and a factor of the leading coefficient (4 here) in the denominator.   We have to include negative factors.

Factors of 9:  -9, -3, -1, 1, 3, 9

Factors of 4: 1, 2, 4

We only have to consider negative numbers for the numerator to get all the possible values.

We just make the list, going through all the numerators one denominator at a time.

Possible rational zeros, i.e. possible rational values for x such that f(x)=0 are

Answer: -9, -3, -1, 1, 3, 9,   -9/2, -3/2, -1/2, 1/2, 3/2, 9/2,   -9/4, -3/4, -1/4, 1/4, 3/4, 9/4

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Jason complete 5/8 of his test and 10/25 of his homework. What fraction of his homework does he still need to complete?
sineoko [7]

Answer:

3/4

Step-by-step explanation:

Because the total homework would be 25/25

\frac{25}{25}-\frac{10}{25} =\frac{15}{25}

15/20 can be reduced to 3/4

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3 years ago
Can someone help me out here ??
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Answer:

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5 0
2 years ago
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Shtirlitz [24]

Answer:

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Step-by-step explanation:

The standard equation of a line in point-slope form is expressed as;

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We can see that both equations given are written in this form with a slope of 1.2. For two lines to be equal, they must have the same slope no matter the point on the lines. Hence the two equations are equal since they have different slopes.

5 0
2 years ago
If f(x) = -3x - 5 and g(x) = 4x - 2, find (F- g)(x).
yan [13]

<u>Answer:</u>

If f(x) = -3x - 5 and g(x) = 4x - 2 then (f - g)(x) = -7x - 3

<u>Solution:</u>

We need to determine the value of (f - g)(x)

Given that the function is f(x) = -3x - 5 and the other function is g(x) = 4x - 2

The value of (f - g)(x) can be found by as follows:

<em>(f - g)(x) = f(x) - g(x)</em>

On substituting the given value of f(x) and g(x) we get

(f - g)(x) = (-3x - 5) - (4x - 2)

Upon solving we get

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3 years ago
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Ilia_Sergeevich [38]

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Hope this helps

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